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3 years ago

The element with the most stable nucleus and smallest mass per particle is

Chemistry

1 answer:

Margaret [11]3 years ago

4 0

"18) the element with the most stable nucleus and smallest mass per particle is:A) uranium.B)argon C) helium."

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If two oceanic plates move towards each other at a convergent boundary, then_____ may occur.

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3 years ago

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Consider the voltaic cellZn(s) + Cu{2+}(aq)--> Zn{2+}(aq)+Cu(s){}=chargeUnder standard conditions, what is the maximum electr

blondinia [14]

Answer:

Max. work done in 60 g of copper plated out is 200472.14 J

Explanation:

Given cell reaction is:

$Zn(s)+Cu^{2+} \rightarrow Zn^{2+}+Cu(s)$

Standard reduction potential of Zn electrode ( $E_{Zn^{2+}/Zn}$ ) is 0.763 V.

Standard reduction potential of Cu electrode ( $E_{Cu^{2+}/Cu}$ ) is -0.337 V.

Copper acts as cathode and Zinc acts as anode.

Cell potential (E) = E° cathode - E° anode

= 0.763 - (-0.337)

= 1.10 V

formula for the work done is as follows:

$W_{max}=-nFE$

Here, n is no. of electron involved in the reaction.

F(Faraday's constant) = 96500

In the given reaction, n = 2

$W_{max}=-nFE\\=-2 \times\ 96500 \times 1.10\\=-212300\ J/mol$

Therefore, 212300 J work is done by reducting 1 mol of copper.

Copper given is 60 g.

Molecular mass of copper is 63.54 g/mol.

$No.\ of\ mol = \frac{60\ g}{63.54\ g/mol}$

Max. work done in 60 g of copper plated out is:

$W_{max}=212300\ J/mol \times \frac{60\ g}{63.54\ g/mol} \\=200472.14\ J$

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3 years ago

Which actions is due to field forces <br>

lisabon 2012 [21]

A field force is a force that acts equally on all the items in it. For example, the force you exert on the chair when you push it acts only on the chair - not on the table, other chairs, etc. around it. Whereas a force like gravity acts equally on everything - on the apple, on the leaves, on the other apples in the tree, etc

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NEW YORK IS A STATE BECAUSE IT IS

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A proton travels at a speed of 2.0 × 106 meters/second. Its velocity is at right angles with a magnetic field of strength 5.5 ×

Finger [1]

So here we are given that the the velocity of the proton ( V ) is 2.0 × $10^6$ meters / second, with a magnetic field of strength 5.5 × $10^{-3}$ tesla. If they each form a right angle, they are hence perpendicular to one another, such that ....

F = q( V × B ),

F = q v B( sin ∅ ),

F = q v B( sin( 90 ) )

.... they form the following formula. Let's go through each of the variables in our formula here -

{ F = Magnetic Force ( which has to be calculated ), q = charge of proton (has charge of 1.602 × $10^{19}$ coulombs ), B = magnetic field }

All we have to do now is plug and chug,

F = ( 1.602 × $10^{19}$ )( 2.0 × $10^6$ )( 5.5 × $10^{-3}$ ) = ( About ) 1.8 × $10^{-15}$ Newtons

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