Since the applied stress required for failure due to crack propagation is still higher than 550 MPa, the ceramic is expected to fail due to overload and not because of the flaws
Explanation:
<u>Plane -Strain Fracture toughness is calculated as</u>
=
б
F=geometry factor of the flaw
б=Stress applied
=Fracture toughness
a=Flaw size
<u>Given that </u>
Internal Flaw,a=0.001cm
Fracture Toughness =45MPa
Tensile Strength б=550 MPa
Geometry Factor,=1
<u>Calculation</u>
An internal Flaw i s 0.001 cm
2a=0.001cm
a=0