Answer:

24.21 m/s
Explanation:
x = Displacement in x direction = 55 m
y = Displacement in x direction = 0
= Height of the ball when the ball is kicked = 1 m
t = Time taken = 4.2 s
= Acceleration due to gravity = 
u = Initial velocity of ball
Displacement in x direction is given by

Displacement in y direction is given by


The ball should be kicked at an angle of 

The initial speed of the ball is 24.21 m/s.
Answer:
the two balls will hit the ground at the same time.
Explanation:
The time of dropping, in the following equation, is related to both the distance travel s and the gravitational acceleration g, which are the same for both ball (if we neglect air resistance), no matter what their mass are.


So the time it takes to drop 2 balls are the same. They will hit the ground at the same time.
Answer:cross-sectional area, and thus surface area, increases the amount of air resistance an object experiences
Explanation:
Answer:
The distance traveled by the ball is 8.5 m
Explanation:
Initial height of the ball, h₁ = 1.5 m above the ground
final height of the ball, h₂ = 5m
Upward distance = distance traveled by the ball from a height of 1.5m to 5m = 5m - 1.5m = 3.5 m
Downward distance = distance traveled by the ball from 5m height to the ground =5m - 0 = 5m
Total distance traveled = upward distance + downward distance
Total distance traveled = 3.5 m + 5m = 8.5 m
Therefore, the distance traveled by the ball is 8.5 m