Answer:
False -
F = G M1 M2 / R^2
So F depends on M1 and M2 and as long either is not zero there will be a gravitational force between them.
Answer:
1.1 x 10⁻⁵m³
Explanation:
Given parameters:
Weight in air = 11.29N
Weight in water = 9.190N
Density of gold = 19320kg/m³
Unknown:
Volume of the secret cavity = ?
Solution:
To solve this problem, we need to find the mass of the secret cavity.
Weight of the cavity = Weight of sculpture in air - Weight of sculpture in water
Weight of cavity = 11.29N - 9.190N = 2.1N
Weight = mass x acceleration due to gravity
Mass =
= 0.2kg
So;
Volume of substance can be determined from the density.
Density =
Volume =
Now insert the parameters and solve;
Volume =
= 1.1 x 10⁻⁵m³
Answer:
The value of final velocity of the first hockey puck
2.3 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
Mass of hockey puck = m
Initial velocity ![v_{1}_{i} = 4.5 \frac{m}{s}](https://tex.z-dn.net/?f=v_%7B1%7D_%7Bi%7D%20%20%3D%204.5%20%5Cfrac%7Bm%7D%7Bs%7D)
From conservation of momentum principal
4.5 m = m
+ m ×
× 3.5
= 1.5 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
0 = m
+ m ×
× 3.5
= - 1.75 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
Now final velocity of first puck
![v_{1} _{f} = \sqrt{v_{1x} _{f}^{2} + {v_{1y} _{f}^{2} }](https://tex.z-dn.net/?f=v_%7B1%7D%20_%7Bf%7D%20%3D%20%5Csqrt%7Bv_%7B1x%7D%20_%7Bf%7D%5E%7B2%7D%20%2B%20%7Bv_%7B1y%7D%20_%7Bf%7D%5E%7B2%7D%20%20%7D)
Put the values in above formula we get
![v_{1} _{f} = \sqrt{(1.5)^{2} + (-1.75)^{2} }](https://tex.z-dn.net/?f=v_%7B1%7D%20_%7Bf%7D%20%3D%20%5Csqrt%7B%281.5%29%5E%7B2%7D%20%2B%20%28-1.75%29%5E%7B2%7D%20%20%7D)
2.3 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
This is the value of final velocity of the first hockey puck.
The books will fall at a very fast rate of 3 mph
Answer: Due to water pressure.
Explanation:
As depth increases so does the pressure.