In calculating the bank discount when discounting an interest-bearing note, which one of the following is not used in the calcul
1 answer:
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<u>Answer:</u>
The amount lost over the 3 years s 2567.25£
<u>Explanation:</u>
where F = final value after n years
I = initial value of the car in 2017 = £18000 (given)
Since the value is depreciated 5% every year for 3 years,
r = percentage rate of depreciation = 5% (given)
n = 3 years
Substituting these values in formula, we get
=
= 15432.75£ which is the value of the car after 3 years
Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.
Answer:
B.The exponent of the solution is –12, the difference of the original exponents.
C.The coefficient of the solution must be greater than or equal to one but less than 10.
D.The quotient is 3.0 ×
Step-by-step explanation:
We are finding the quotient of the expression below in scientific notation
The following conclusions can be drawn
B.The power of 10 in the solution is –12, the difference of the original exponents.
C.The coefficient is 3, which is greater than or equal to one but less than 10.
D.The quotient is 3.0 ×