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dexar [7]
3 years ago
7

Which statements describe the death of stars? Check all that apply.

Chemistry
2 answers:
baherus [9]3 years ago
6 0

Answer:

a,b

Explanation:

Sveta_85 [38]3 years ago
5 0

Answer:A and B

Explanation:a stats final stages of life depend on its mass and stars die when they run out of fuel

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Is it difficult or easy to obtain hydro power
Paha777 [63]

Answer:yes

Explanation:

cause yes

3 0
2 years ago
Describe where a hydrogen bond can form among water molecules.
stiv31 [10]

Answer:

                 In water hydrogen bonding formed between partially negative oxygen and partially positive hydrogen atoms.

Explanation:

                  Hydrogen bond is a partially electrostatic attraction between hydrogen (H), which is bonded to a more electronegative atom such as nitrogen (N), oxygen (O) or fluorine (F), and another adjacent atom bearing a lone pair of electrons.

                   In water molecule hydrogen and oxygen have difference in electronegativity, due to which dipoles are form. One is partial positive on hydrogen atom and other is partial negative on oxygen atom. The electrostatic attraction occur between two oppositely charged poles which is known as hydrogen bonding.

4 0
3 years ago
Practice It!
Ostrovityanka [42]

Answer:

Explanation:

Space exploration technology has helped us explore the Moon and see images of far off galaxies.

Space technology may help us inhabit another planet or live in space in the future.

These are the correct statements

4 0
3 years ago
Read 2 more answers
A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of
mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.125

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.125=e^{-0.00440\times t}

t = 473 year

8 0
3 years ago
Although both N2 and 02 are naturally present in the air we breathe, high levels of NO and NO2 in the atmosphere occur mainly in
joja [24]

Answer:

(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.

(b) Pressure has no effect since the change in the number of moles is zero.

Explanation:

Hello,

In this case, one could represent the given reaction as:

N_2(g)+O_2(g)+ \Delta _rH \leftrightarrow 2NO

Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.

Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:

\Delta \nu =2-1-1=0

Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:

Kp=Kc(RT)^{\Delta \nu }

Thus, since \Delta \nu =0, Kp=Kc, so no effect in concentration is due to the pressure.

Best regards.

6 0
3 years ago
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