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Nezavi [6.7K]
3 years ago
13

An electric dipole with its center located at the origin of a Cartesian coordinate system oscillates along the x axis, creating

an electromagnetic wave.
Part A: At a position on the z axis far from the origin, what is the polarization of the wave?
Part B: At a position on the axis far from the origin, what is the polarization of the wave?
Physics
1 answer:
Ainat [17]3 years ago
5 0

Answer:

The wave propagates on the z axis and the polarization is linear on the x axis

Explanation:

Part A

When the two dipole charges oscillate they form a fluctuating wave that propagates in the perpendicular direction, so if the oscillation of the magnetic field is on the axis and the propagation of the wave occurs on the z-axis.

The polarization of the electric wave is equal to the direction of the electric field, therefore as the field oscillates on the x-axis the polarization is also on the x-axis and is linearly polarized.

Part B

The wave propagates on the z axis and the polarization is linear on the x axis

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A person is walking briskly in a straight line. The figure shows a graph of the person’s position x as a function of time t. Wha
Nina [5.8K]

The average velocity over the interval 6\le t\le 10 is

\dfrac{x(10)-x(6)}{10\,\mathrm s-6\,\mathrm s}=\dfrac{6\,\mathrm m-2.67\,\mathrm m}{4\,\mathrm s}=0.8325\,\dfrac{\mathrm m}{\mathrm s}

where x(t) is the person's position at time t. I've taken the liberty of estimating x(6)\approx2.67\,\mathrm m. The closest choice among the answers is 0.8\,\dfrac{\mathrm m}{\mathrm s}.

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3 years ago
High-voltage power lines are a familiar sight throughout the country. The aluminum wire used for some of these lines has a cross
goblinko [34]

Answer:

Explanation:

For resistance of a wire , the formula is as follows

R = ρ L / S

where ρ is specific resistance , L is length and S is cross sectional area

Given L = 14 000 m ,

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specific resistance of aluminum = 2.8 x 10⁻⁸ ohm-meter

Putting the values in the formula

R = 2.8 x 10⁻⁸ x 14 x 10³ /  (4.8 x 10⁻⁴ )

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When a flat slab of transparent material is placed under water, the critical angle for light traveling from the slab into water
Novosadov [1.4K]

Answer:

(a) 40.6 degree

Explanation:

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Use Snell's law

refractive index of water with respect to slab

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\frac{\mu _{w}}{\mu _{s}}=0.866

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1 / 1.536 = Sin C

C = 40.6 degree

3 0
3 years ago
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