Answer:
d. CH3CH2OH
Explanation:
Molecular solution are solutions when a molecular compound is dissolved in them.
CH3CH2OH represents Ethanol or alcohol carrying "OH" group and is a molecule. CH3CH2OH or Ethanol forms a molecular solution in water.
The equation for Ethanol dissolving in water as follows:
CH3CH2OH(l) => CH3CH2OH(aq)
CH3CH2OH srays together as molecules. During dissolving, ethanol molecule fit into spaces between water molecules and completely mix with water.
While HCN, CH3COOH and Ba(OH)2 form ionic solution.
Hence, the correct option is d. CH3CH2OH.
Answer:
0.8162 gramos de plomo por gramo de yodo
1.633 gramos de plomo por gramo de yodo
Explanation:
Asumiendo una base de 100 gramos para cada compuesto:
Primer compuesto:
Gramos plomo: 44.94g
Gramos de yodo: 100-44.94g = 55.06g
Así, la masa de plomo por gramos de yodo para el primer compuesto es:
44.94g plomo / 55.06g Yodo =
<em>0.8162 gramos de plomo por gramo de yodo</em>
<em></em>
Segundo compuesto:
Gramos plomo: 62.02g
Gramos de yodo: 100-62.02g = 37.98g
La masa de plomo por gramos de yodo para el segundo compuesto es:
62.02g plomo / 37.98g Yodo =
<em>1.633 gramos de plomo por gramo de yodo</em>
Petroleum is a potential.
yeah that's my guess.
Answer: 20 mg Te-99 remains after 12 hours.
Explanation: N(t) = N(0)*(1/2)^(t/t1/2)
N(t) = (80 mg)*(0.5)^(12/6)
N(t) = 20 mg remains after 12 hours
