Answer:
310.53 g of Cu.
Explanation:
The balanced equation for the reaction is given below:
CuSO₄ + Zn —> ZnSO₄ + Cu
Next, we shall determine the mass of CuSO₄ that reacted and the mass Cu produced from the balanced equation. This can be obtained as follow:
Molar mass of CuSO₄ = 63.5 + 32 + (16×4)
= 63.5 + 32 + 64
= 159.5 g/mol
Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g
Molar mass of Cu = 63.5 g/mol
Mass of Cu from the balanced equation = 1 × 63.5 = 63.5 g
Summary:
From the balanced equation above,
159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.
Finally, we shall determine the mass of Cu produced by the reaction of 780 g of CuSO₄. This can be obtained as follow:
From the balanced equation above,
159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.
Therefore, 780 g of CuSO₄ will react to produce = (780 × 63.5)/159.5 = 310.53 g of Cu.
Thus, 310.53 g of Cu were obtained from the reaction.
The danger from radon gas would most likely be greatest in well-insulated homes. It is a toxic gas.
<h3>What is radon gas?</h3>
Radon is a naturally radioactive gas generated from different elements such as uranium or radium.
Radon is generated when these radioactive materials naturally decompose in the soils and/or rocks.
Radon is highly toxic and therefore this gas must be avoided to maintain healthy conditions in a home.
Learn more about the radon gas here:
brainly.com/question/1121893
Explanation:
The similarities between chemical and physical changes include change in state of matter and both process involve change in energy.
Chemical changes of a substance results in the formation of entirely new substances. These changes are not reversible.
Physical changes results in the change of the state of the substance which can be reversed.
However, both chemical and physical changes results in change of state of matter and both process results in change in energy.
Thus, we can conclude that the similarities between chemical and physical changes include change in state of matter and both process involve change in energy.
(it's alre answered but here it again 'NOTE: not my answer')
Answer:
The answer to your question is: letter c
Explanation:
Data
V1 = 612 ml n1 = 9.11 mol
V2 = 123 ml n2 = ?
Formula
n2 = 1.83 mol
Answer:
d) 2.7 mol
Explanation:
limit reagent is H2:
∴ Mw H2 = 2.016 g/mol
∴ Mw N2 = 28.0134 g/mol
⇒ moles NH3 = (4.0 moles H2)×(2 mol NH3/3mol H2)
⇒ moles NH3 = 2.666 mol
⇒ moles NH3 ≅ 2.7 mol
