Answer:
168.4 mL
Explanation:
Data Given
initial volume V1 of gas in balloon = 100 mL
initial pressure P1 of gas in balloon = 3.2 atm
final pressure P2 of gas in balloon = 1.9 atm
final volume V2 of gas in balloon = ?
Solution:
This problem will be solved by using Boyle's law equation at constant Temperature.
The formula used
P1V1 = P2V2
As we have to find out Volume, so rearrange the above equation
V2 = P1V1 / P2
Put value from the data given
V2 = 100 mL x 3.2 atm / 1.9 atm
V2 = 168.4 mL
So the final Volume of gas in baloon = 168.4 mL
K5O2
convert grams to moles, divide both by the smallest mole mass, multiply that until hole.
30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2
Answer:2817.8
Explanation:multiply the value by 365
It would 47.7 because you would have to both minus the number together.
10HSiCl3 + 15H2O = H10Si10O15 + 30HCl
