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3 years ago

Please solve this a,b,c,d

Chemistry

1 answer:

Levart [38]3 years ago

8 0

Answer:

The answer should br C

Explanation:

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Kate’s blood volume is 3.8L. Before treatment,if her blood glucose was 170 mg/dL, how many grams of glucose were in her blood?

LiRa [457]

Answer:

6.460 gm is the correct answer .

Explanation:

Given

Kate’s blood volume= $3.8L$

blood glucose= $170\ mg/dL$

As we know that

$1\ dL= 10^{-1}\ litre$

The $10^{-1}$ includes the blood glucose of the $170\ mg/dL,$

So $3.8L.$ of the Kate’s blood volume can be determined by

$=\ \frac{170 * 3.8 }{10^{-1} }$

$=170 * 38 \ mg$

$=6460\ mg$

To convert into the gm we have divided by the 1000

$6.460 \ gm$

Therefore the glucose in her blood=

$6.460 \ gm$

3 0

3 years ago

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What is Co³⁺ and Co¹⁺

WITCHER [35]

Answer:

https://clever.com/

Explanation:

6 0

3 years ago

According to the following reaction, how many grams of water are produced in the complete reaction of 29.7 grams of ammonia? 4 N

Gnesinka [82]

Answer: The mass of water produced in the reaction is 47.25 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of ammonia = 29.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

$\text{Moles of ammonia}=\frac{29.7g}{17g/mol}=1.75mol$

The given chemical reaction follows:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$

By stoichiometry of the reaction:

4 moles of ammonia produces 6 moles of water.

So, 1.75 moles of ammonia will produce = $\frac{6}{4}\times 1.75=2.625mol$ of water.

Now, calculating the mass of water by using equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 2.625 moles

Putting values in equation 1, we get:

$2.625mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=47.25g$

Hence, the mass of water produced in the reaction is 47.25 grams.

3 0

3 years ago

in an oversight in the experiment jamie did not add the 4-5 additional drop of 6M JNO3. as result, will the reported number of m

kaheart [24]

The reported number of moles will be too low since the additional amount of oxygen is not included. It may be 6 drops but the molarity of the solution is 6M. this meas that for every ml of the JNO3 solution there is 6 moles of JNO3. In every mole of JNO3 there are 3 moles of oxygen. So in every drop of oxygen there are 18 moles of oxygen.

6 0

3 years ago

Help me ASAP !!!!!!!!!!!

dedylja [7]

Answer:

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Explanation:

4 0

3 years ago