126 grams of H2O is formed.
Explanation:
Data given:
volume of the gas = 88 Liters
pressure = 720 mm Hg or 0.947 atm
temperature T = 22 Degrees or 295.15 K
R = 0.08021 atm L/mole K
n =?
The formula is used is of ideal gas law to know the number of moles of CH4 undergoing combustion.
PV = nRT
n = 
putting the values in the equation
= 0.947 X 88/ 0.08021 X 295.15
n = 3.5 moles
balanced reaction for combustion of methane
CH4 + O2 ⇒ CO2 + 2H20
1 mole of CH4 undergoes combustion to form 2 moles of water
3.5 moles will give x moles of water
2/1 = x/3.5
x = 7 moles of water (atomic mass of water = 18 gram/mole)
mass = atomic mass x number of moles
mass = 18 x 7
=126 grams of water is formed.
Answer:
Group 8 or Group 0
Explanation:
Group 8 or Group 0 are generally inert gases with Helium as the first member in that group. Their complete duplet (in the case of Helium) and Octet (in the case of Neon) configuration makes them very stable and chemically un-reactive.
Answer:



Explanation:
Molar mass of NaCl = 58.44 g/mol
Mass of NaCl = 195 g
Volume of solution = 4.05 L
Molarity of solution is

The molarity of the solution is 
Moles of NaCl = 4.63 mol
Volume is given by

The volume of the solution that contains the required amount NaCl is 
Volume of solution = 
Moles of solution is given by

The number of moles of NaCl is
.
No it’s a very easy assignment