Which method is the first step when scientists communicate their scientific results?

SYNTHESIS OFCARBONATECTIONLABORATORY SIMULATIONLab Data- X99.00.10CollectedVolume sodium carbonate (mL)Molarity sodium carbonate

evablogger [386]

Answer:

$\begin{gathered} \text{Limiting Reagent = Sodium Carbonate} \\ \text{Percent Yield = 98\%} \end{gathered}$

Explanation:

The chemical reaction talks about the synthesis of calcium carbonate

It is from the reaction between sodium carbonate and calcium chloride

Let us write the equation of reaction as follows:

$Na_2CO_{3(aq)}+CaCl_{2(aq)}\text{ }\rightarrow2NaCl_{(s)\text{ }}+CaCO_{3(aq)}$

Firstly, we want to get the expected mass of calcium carbonate

This speaks about getting the theoretical yield based on the equation of reaction

From the data collected, 90 ml of 0.20 M (mol/L) of sodium carbonate gave calcium carbonate

We need to get the actual number of moles of sodium carbonate that reacted

We can get this by multiplying the volume by the molarity (kindly note that we have to convert the volume to Liters by dividing by 1000)

Thus, we have it as:

$\frac{90}{1000}\times\text{ 0.1 = 0.009 moles}$

Hence, we see that 0.009 moles of sodium carbonate reacted theoretically

Since 1 mole of sodium carbonate gave 1 mole calcium carbonate, it is expected that 0.009 mole of sodium carbonate will give 0.009mole of calcium carbonate

What we have to do now is to get the theoretical grams of calcium carbonate produced

That would be the product of the number of moles of calcium carbonate and its molar mass

The molar mass of calcium carbonate is 100 g/mol

The theoretical yield (expected mass) is thus:

$100\text{ g/ mol }\times\text{ 0.009mol = 0.9 g}$

Finally, we proceed to get the percentage yield which is calculated using the formula below:

$\text{Percent Yield = }\frac{Actual\text{ yield}}{\text{Theoretical yield}}\times\text{ 100 \%}$

The actual yield is the observed mass which is given as 0.88 g

The percent yield is thus:

$\frac{0.88}{0.9}\times\text{ 100 = }98\text{ \%}$

7 0

1 year ago

How many moles of koh are needed to neutralize 0.4 moles of hno3

Julli [10]

Answer:

0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

Explanation:

The equation of the reaction is

KOH(aq) + HNO3(aq) ------> KNO3(aq) + H2O(l)

This is a neutralization reaction. A neutralization reaction is a reaction between an acid and a base to form salt and water only.

Having written the balanced chemical reaction equation, we can now solve the prob!em stoichiometrically.

From the balanced reaction equation;

1 mole of KOH is required to neutralize 1 mole of HNO3

Therefore x moles of KOH is required to neutralize 0.4 moles of HNO3

x= 1×0.4/1 = 0.4 moles

Therefore, 0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

7 0

3 years ago

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Which of the following solutions will freeze at the lowesttemperature? a.1 mole C6H12O6in 500 g water b.1 mole MgF2in 500 g wate

AlladinOne [14]

Answer:

Option d.

1 mole AlCl3in 500 g water

Explanation:

ΔT = Kf . m . i

Freezing T° of solution = - (Kf . m . i)

In order to have the lowest freezing T° of solution, we need to know which solution has the highest value for the product (Kf . m . i)

Kf is a constant, so stays the same and m stays also the same because we have the same moles, in the same amount of solvent. In conclussion, same molality to all.

i defines everything. The i refers to the Van't Hoff factor which are the number of ions dissolved in solution. We assume 100 & of ionization so:

a. Glucose → i = 1

Glucose is non electrolytic, no ions formed

b. MgF₂ → Mg²⁺ + 2F⁻

i = 3. 1 mol of magnessium cation and 2 fluorides.

c. KBr → K⁺ + Br⁻

i = 2. 1 mol potassium cation and 1 mol of bromide anion

d. AlCl₃ → Al³⁺ + 3Cl⁻

i = 4. 1 mol of aluminum cation and 3 mol of chlorides.

Kf . m . 4 → option d will has the highest product, therefore will be the lowest freezing point.

5 0

3 years ago

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What is the correct name for this formula: BaCl2

Inessa05 [86]

BaCI2 stands for Barium Chloride. Hope this helps!

3 0

3 years ago

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If nothing eats a hawk what might eventually happen to the energy that is stored in its body

prisoha [69]

✷ Question: If nothing ever eats a hawk, what might eventually happen to the energy that is stored in its body?

✐ Answer: When the hawk passes away, the body will decompose like all living creatures. The hawk's energy throughout the body will be pumped back to the system, forming a lot of energy. 
Hope that helps! ★ If you have further questions or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia

6 0

4 years ago

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