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3 years ago

13 is 26 percent of what number?

Mathematics

2 answers:

Lyrx [107]3 years ago

5 0

100 because every percent is is based out of 100

Leokris [45]3 years ago

3 0

i think Answer is : 50

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The length of a rectangle is 7 cm more than 4 times the width. If the perimeter of the rectangle is 44 cm, what are its dimensio

Alexxandr [17]

Answer:

3 by 19

Step-by-step explanation:

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3 years ago

Determine the domain and the range for this relationship.

Vladimir [108]

Answer:

domain 0 ≤ y ≤ 72 and the range is 0 ≤ y ≤ 6

Step-by-step explanation:

I hope this helps you.

7 0

2 years ago

A cab company charges a flat fee of $5.00 and then an additional $0.45 per mile. Write an equation expressing the cost of a ride

Oliga [24]

The equation representing the cost of the ride is R = $5 + $0.45dd.

The flat fee charged is the fixed cost. This cost remains constant regardless of the distance travelled. The additional fee is the variable cost. It increases with the distance travelled.

<h3> Derivation of the equation that represents cost of the ride.</h3>

Total cost = fixed cost + (variable cost x miles driven)

R = $5 + $0.45dd

To learn more about flat fees, please check: brainly.com/question/25879561

6 0

3 years ago

Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =

marta [7]

Answer:

The integral for the arc of length is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

By using Simpon’s rule we get: 1.5355453

And using technology we get: 2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

$\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx$

We need the derivative of the function:

$f'(x)=\frac{1}{x}$

And we need it squared:

$[f'(x)]^2=\frac{1}{x^2}$

Then the integral is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

Now, the Simposn’s rule with n=4 is:

$\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)$

In this problem:

$a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}$

So, the Simposn’s rule formula becomes:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then simplifying a bit:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$