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iren2701 [21]
4 years ago
11

Please helppp ! Is my choice right ?

Physics
1 answer:
grin007 [14]4 years ago
6 0
Yes you are right because if both of the photons are the same nothing is really happening thereafter c is the correct answer.
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A capacitor with initial charge q0 is discharged through a resistor. a) In terms of the time constant τ, how long is required fo
-BARSIC- [3]

Answer:

It would take \tau(\ln 9 - \ln 8) time for the capacitor to discharge from q_0 to \displaystyle \frac{8}{9} \, q_0.

It would take \tau(\ln 9 - \ln 7) time for the capacitor to discharge from q_0 to \displaystyle \frac{7}{9}\, q_0.

Note that \ln 9 = 2\,\ln 3, and that\ln 8 = 3\, \ln 2.

Explanation:

In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is \tau, and the initial charge of the capacitor be q_0. Then at time t, the charge stored in the capacitor would be:

\displaystyle q(t) = q_0 \, e^{-t / \tau}.

<h3>a)</h3>

\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{8}{9}\, q_0.

Apply the equation \displaystyle q(t) = q_0 \, e^{-t / \tau}:

\displaystyle \frac{8}{9}\, q_0 = q_0 \, e^{-t/\tau}.

The goal is to solve for t in terms of \tau. Rearrange the equation:

\displaystyle e^{-t/\tau} = \frac{8}{9}.

Take the natural logarithm of both sides:

\displaystyle \ln\, e^{-t/\tau} = \ln \frac{8}{9}.

\displaystyle -\frac{t}{\tau} = \ln 8 - \ln 9.

t = - \tau \, \left(\ln 8 - \ln 9\right) = \tau(\ln 9 - \ln 8).

<h3>b)</h3>

\displaystyle q(t) = \left(1 - \frac{1}{9}\right) \, q_0 = \frac{7}{9}\, q_0.

Apply the equation \displaystyle q(t) = q_0 \, e^{-t / \tau}:

\displaystyle \frac{7}{9}\, q_0 = q_0 \, e^{-t/\tau}.

The goal is to solve for t in terms of \tau. Rearrange the equation:

\displaystyle e^{-t/\tau} = \frac{7}{9}.

Take the natural logarithm of both sides:

\displaystyle \ln\, e^{-t/\tau} = \ln \frac{7}{9}.

\displaystyle -\frac{t}{\tau} = \ln 7 - \ln 9.

t = - \tau \, \left(\ln 7 - \ln 9\right) = \tau(\ln 9 - \ln 7).

7 0
3 years ago
What is the relationship between "friction" and "thermal energy?"
SCORPION-xisa [38]
When temperature increases, particles in an object speed up, which means an increase in thermal energy<span>. Since the particles are moving more now, the potential energy decreases, therefore kinetic energy increases. Overall,when temperature go up, thermal energy go up, which leads to an increase to kinetic energy.</span>
4 0
3 years ago
A projectile of mass 6.8 kg kg is shot horizontally with an initial speed of 14.5 m/s from a height of 26.7 m above a flat deser
sleet_krkn [62]

Answer:

Explanation:

Given

mass of projectile m=6.8\ kg

initial horizontal speed u_x=14.5\ m/s

height h=26.7\ m

Considering vertical motion

velocity gained by projectile during 26.7 m motion

v^2-u^2=2 as

v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2-(0)^2=2\times (9.8)\times (26.7)

v=\sqrt{523.32}

v=22.87\ m/s

Horizontal velocity will remain same as there is no acceleration

final velocity v_{net}=\sqrt{(v)^2+(u_x)^2}

v_{net}=\sqrt{733.57}=27.08\ m/s

Initial kinetic Energy K_i=\frac{1}{2}mu_x^2

K_i=\frac{1}{2}\times 6.8\times (14.5)^2=714.85\ J

Final Kinetic Energy K_f=\frac{1}{2}mv_{net}^2

K_f=\frac{1}{2}\times 6.8\times (27.08)^2

K_f=2493.30\ J

Work done by all the force is equal to change in kinetic Energy of object

Work done by gravity is W_g

W_g=\Delta K

W_g=2493.30-714.85=1778.45\ J  

8 0
3 years ago
You push a 10 n object 10 meters. How much work was done on the object
Contact [7]
Work= Force * Distance
Work= 10N * 10m
Work= 100J
3 0
3 years ago
good morning to you all! someone please answer this, ill give you brainliest and you will earn 50 points.
Shalnov [3]

Natural hazards do not have to be natural disasters. What are some of the ways modern technology can help prevent future natural disasters?

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  • <em>Monitoring</em><em> </em><em>seismic</em><em> </em><em>activity</em><em> </em><em>using</em><em> </em><em>seismographs</em>

<u>Satellite</u><u> </u><u>imaging</u><u> </u><u>helps</u><u> </u><u>in</u><u> </u><u>predicting</u><u> </u><u>disasters</u><u> </u><u>like</u><u> </u><u>hurricane</u><u>.</u><u> </u><u>Before</u><u> </u><u>hurricane</u><u>,</u><u> </u><u>the</u><u> </u><u>satellite</u><u> </u><u>can</u><u> </u><u>help</u><u> </u><u>detect</u><u> </u><u>the</u><u> </u><u>movements</u><u> </u><u>in</u><u> </u><u>ocean</u><u>.</u><u> </u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u>Seismographs</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>devices</u><u> </u><u>that</u><u> </u><u>respond</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>ground</u><u> </u><u>shaking</u><u> </u><u>before</u><u> </u><u>volcanic</u><u> </u><u>eruption</u><u>,</u><u> </u><u>earthquake</u><u> </u><u>and</u><u> </u><u>explosions</u><u>.</u>

3 0
2 years ago
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