Answer:
4.19 km and 107.35 degrees north of east
Explanation:
So in the end, the truck is (2.6 + 1.4 = 4km) north and 1.25 km west from the warehouse. We can use the Pythagorean formula to calculate the magnitude and direction α of the truck displacement from the warehouse:
km
north or west or (180 - 72.65) = 107.35 degrees north of east
Work= Force in the direction of displacement*displacement.
You know the force in the direction of displacement (horizontally) and the displacement. So,
W=130*11=1430
Therefore, the work done is 1,430 Joules
Answer:
15.7m/s
Explanation:
To solve this problem, we use the right motion equation.
Here, we have been given the height through which the ball drops;
Height of drop = 14.5m - 1.9m = 12.6m
The right motion equation is;
V² = U² + 2gh
V is the final velocity
U is the initial velocity = 0
g is the acceleration due to gravity = 9.8m/s²
h is the height
Now insert the parameters and solve;
V² = 0² + 2 x 9.8 x 12.6
V² = 246.96
V = √246.96 = 15.7m/s
