The final speed of an airplane is v = 92.95 m/s
The rate of change of position of an object in any direction is known as speed i.e. in other word, Speed is measured as the ratio of distance to the time in which the distance was covered.
Solution-
Here given,
Acceleration a= 10.8 m/s2 .
Displacement (s)= 400m
Then to find final speed of airplane v=?
Therefore from equation of motion can be written as,
v²=u²+ 2as
where, u is initial speed, v is final speed ,a is acceleration and s is displacement of the airplane. Therefore by putting the value of a & s in above equation and (u =0) i.e. the initial speed of airplane is zero.
v²= 2×10.8 m/s²×400m
v²=8640m/s
v=92.95m/s
hence the final speed of airplane v =92.95m/s
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Answer:
yes
Explanation:
this is simple
the horizontal line is adjacent
the vertical line is opposite
recall that cos x=adj/hyp
adj=hyp(cos x)
while opp=hyp(sin x)
Answer:
The strength of the magnetic field is 3.5 x 10⁻³ T
Explanation:
Given;
magnitude of the magnetic flux , Φ = 5.90 x 10⁻⁵ T·m²
angle of inclination of the field, θ = 42.0°
radius of the circular plate, r = 8.50 cm = 0.085 m
Generally magnetic flux in a uniform magnetic field is given as;
Φ = BACosθ
where;
B is the strength of the magnetic field
A is the area of the circular plate
Area of the circular plate:
A = πr²
A = π (0.085)² = 0.0227 m²
The strength of the magnetic field:
B = Φ / ACosθ
B = ( 5.90 x 10⁻⁵) / ( 0.0227 x Cos42)
B = 3.5 x 10⁻³ T
Therefore, the strength of the magnetic field is 3.5 x 10⁻³ T
More sales of traditional, large cars are the most likely consequence of falling petroleum prices.
<h3>Explanation</h3>
Since the majority of conventional, large cars employ combustion engines, these engines need petroleum fuel to operate.
As a result, <em>Choice C—more sales of conventional, large cars</em>—is one of the effects of dropping oil prices that is most likely to occur.
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Answer:
The acceleration of the centre of mass of spool A is equal to the magnitude of the acceleration of the centre of mass of spool B.
Explanation:
From the image attached, the description from the complete question shows that the two spools are of equal masses (same weight due to same acceleration due to gravity), have the same inextensible wire with negligible mass is attached to both of them over a frictionless pulley; meaning that the tension in the wire is the same on both ends.
And for the acceleration of both spools, we mention the net force.
The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.
For this system, the net force on either spool is exactly the same in magnitude because the net force is a difference between the only two forces acting on the spools; the tension in the wire and their similar respective weights.
With the net force and mass, for each spool equal, from
ΣF = ma, we get that a = ΣF/m
Meaning that the acceleration of the identical spools is equal also.
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