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cricket20 [7]
4 years ago
8

A block of mass 3.7 kg, which has an initial velocity of 7.9 m/s at time t = 0, slides on a horizontal surface. Calculate the wo

rk that must be done on the block to bring it to rest. Answer in units of J.
Physics
2 answers:
Lady_Fox [76]4 years ago
5 0

Answer:

115.6 J

Explanation:

m = mass of the block = 3.7 kg

v_{f} = final speed of the block = 0 ms⁻¹

v_{o} = initial speed of the block = 7.9 ms⁻¹

W = work done on the block

Using work done - change in kinetic energy theorem, we have

W = (0.5) m (v_{o}^{2} - v_{f}^{2})\\W = (0.5) (3.7) (7.9^{2} - 0^{2})\\W = 115.6 J

quester [9]4 years ago
4 0

115.46 J work must be done on the block to bring it to rest.

Explanation:

From law of conservation of energy, neglecting the friction, we know that:

<h3>Work done to stop the body = Kinetic energy lost by the body</h3>

Work done to stop the body = 1/2 mv²

Work done to stop the body = 1/2 (3.7 kg) (7.9 m/s)²

Work done to stop the body = <em><u>115.46 J</u></em>

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