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Black_prince [1.1K]
3 years ago
9

The rate constant for this first‑order reaction is 0.900 s − 1 at 400 ∘ C. A ⟶ products How long, in seconds, would it take for

the concentration of A to decrease from 0.600 M to 0.300 M?
Chemistry
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

first-order reaction is 0.300 s–1 at 400 °C.. ... (in seconds) would it take for the concentration of A to decrease from 0.900 M

Explanation:

yep thats all i know

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What kind of reaction does Iron (III) and copper (II) sulfate solution produce?
ivanzaharov [21]

Answer:

The answer to your question is Single replacement

Explanation:

Types of reaction in Chemistry

Synthesis           two or more reactants combine to produce one single product

Decomposition      one reactant splits producing two or more products

Single replacement  One element replaces a similar one in a compound.

Double replacement Two compounds interchange their cations and anions.

Combustion one compound reacts with oxygen to produce carbon dioxide and water.

Reaction given

                      Fe⁺²  +  CuSO₄  ⇒   Cu + FeSO₄

This is a single replacement reaction

4 0
3 years ago
Read 2 more answers
1 . a chemical bond formed by the electrostatic attraction between ions covalent bond
liberstina [14]

Explanation:

When there occurs sharing of electrons between two chemically combining atoms then it forms a covalent bond. Generally, a covalent bond is formed between two non-metals.

An ionic bond is defined as the bond formed due to transfer of one or more number of electrons from one atom to another. An ionic bond is always formed between a metal and a non-metal.

Every atom of an element will have orbitals in which electrons are found. These orbitals are known as energy level.

A molecule is defined as the smallest particle present in a substance or atom.

A metallic bond is formed due to mobile valence electrons shared by positive nuclei in a metallic crystal.

Thus, we can conclude that given statements are correctly matched as follows.

1).  a chemical bond formed by the electrostatic attraction between ions - ionic bond

2).  a chemical bond formed by two electrons that are shared between two atoms - covalent bond

3). the orbitals of an atom where electrons are found - energy level

4).  the smallest particle of a covalently bonded substance - molecule

5).  a bond characteristic of metals in which mobile valence electrons are shared among positive nuclei in the metallic crystal - metallic bond

7 0
2 years ago
How many moles of FeCI3 are present in 345.0 g FeCI3
Sphinxa [80]

Answer:

\boxed {\boxed {\sf About \ 2.127 \ moles \ of \ FeCl_3}}

Explanation:

To convert from moles to grams, the molar mass must be used.

1. Find Molar Mass

The compound is iron (III) chloride: FeCl₃

First, find the molar masses of the individual elements in the compound: iron (Fe) and chlorine (Cl).

  • Fe:  55.84 g/mol
  • Cl:  35.45 g/mol

There are 3 atoms of chlorine, denoted by the subscript after Cl. Multiply the molar mass of chlorine by 3 and add iron's molar mass.

  • FeCl₃: 3(35.45 g/mol)+(55.84 g/mol)=162.19 g/mol

This number tells us the grams of FeCl₃ in 1 mole.

2. Calculate Moles

Use the number as a ratio.

\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Multiply by the given number of grams, 345.0.

345.0 \ g \ FeCl_3 *\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Flip the fraction so the grams of FeCl₃ will cancel.

345.0 \ g \ FeCl_3 *\frac{1 \ mol \ FeCl_3}{162.19 \ g \ FeCl_3}

345.0 *\frac{1 \ mol \ FeCl_3}{162.19 }

\frac{345.0 \ mol \ FeCl_3}{162.19 }

Divide.

2.12713484 \ mol \ FeCl_3

3. Round

The original measurement of grams, 345.0, has 4 significant figures. We must round our answer to 4 sig figs.

For the answer we calculated, that is the thousandth place.

The 1 in the ten thousandth place tells us to leave the 7 in the thousandth place.

\approx 2.127 \ mol \ FeCl_3

There are about <u>2.127 mole</u>s of iron (III) chloride in 345.0 grams.

6 0
2 years ago
What is the independent variable in this reaction
jolli1 [7]

Answer:

Explanation:

what wheres the answer???

6 0
3 years ago
A chemist determines by measurements that 0.0550 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of
shtirl [24]

The mass of nitrogen gas that participated in the chemical reaction is 1.54g

HOW TO CALCULATE MASS OF AN ELEMENT:

  • Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;

  • mass (M) = molar mass (MM) × number of moles (n)

According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.

  • The molecular mass of nitrogen gas (N2) = 14.01(2)

= 28.02g/mol

Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:

  • Mass (g) = 0.0550 mol × 28.02 g/mol

  • Mass = 1.5411

Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g

Learn more: brainly.com/question/18269198

6 0
2 years ago
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