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4 years ago

Explain why the energy produced by burning wood in a campfire is energy from the sun

Physics

1 answer:

stellarik [79]4 years ago

3 0

When you rub wood together fast the sun shines light on it so much light it makes a fire

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Ball B, with a mass of 30kg, is moving to the left at 10 m/s. With what velocity should ball A, with a mass of 10kg, move to the

bogdanovich [222]

Using the conservation of momentumwhere momentum = mass x velocity
so the let x be the initial velocity of the ball B

(30 kg) (-10 m/s) + (10 kg) (x) = (30 kg) (30 m/s) + ( 10 kg) (-10 m/s)
-300 + 10 x = 900 - 10010x = 900 - 100 + 30010x = 1100x = 1100 / 10x = 110 m/s

6 0

3 years ago

How do i do this is hard

Zolol [24]

Answer:

I believe it would be E)none of the above.

Explanation:

7 0

3 years ago

Bowling balls can be made from a variety of substances and are required to have a circumference of roughly 27.2 inches. The cons

Daniel [21]

Answer:

The bowlling shell's thickness is 2.7"

Explanation:

The geometry of the problem is based in the differences between the volumes in a small sphere and a spherical shell, both objects compose the total volume of the bowling ball.

The equivalence in the total ball height and the equivalent height in the fluid (in this case water displacement of half ball volume) is used for calculating the forces state that allows the static balance of the ball and the flotation force from the fluid (Archimedes principle).

In the image is showed the formulation.

4 0

4 years ago

Which statement about convection in the Earth's mantle is true?

marissa [1.9K]

Answer:

All of these

Explanation:

Mantle convection causes tectonic plates to move around and passes heat on the earth surface in forms of lava and magma.

Hope it helps!

4 0

3 years ago

Hello, I need help. Due right now

ryzh [129]

Answer: See below

Explanation:

$\\ \mathrm{Given:} \\\mathrm{Mass \ of \ first \ car}$\left(m_{1}\right)=1383 \mathrm{~kg}$ \\ Velocity $\left(\overrightarrow{V_{1}}\right)=-11.2\ {\math} \mathrm{m} / \mathrm{s}$\\ Mass of second car -$\left(m_{2}\right)=1732 \mathrm{~kg}$\\ Velocity $\left(\vec{v}_{2}\right)=31.3 {\math} \mathrm{m} / \mathrm{s}$$

$m_{1} \vec{v}_{1}+m_{2} \vec{v}_{2}=\left(m_{1}+m_{2}\right) \vec{v} \\1383(-11.2 {\math})+1732(31.3 {\math}) \\=(1383+1732) \vec{v} \\-15489.6 {\math}+54211.6 {\math}=3115 \vec{v} \\ \vec{v}=(17.4 {\math}-4.972 {\math}) \ \mathrm{m/s}$

$\text { So magnitude } \vec{|v|} =\sqrt{(17.4)^{2}+(-4.972)^{2}} \\ =\sqrt{327.605} \\ =18.099 \mathrm \ {m/s} \\$

$\text { Direction } \\\theta=\tan ^{-1}\left(\frac{-4.972}{17.4}\right) \\\theta=-15.945^{\circ}\end{gathered}$

Therefore, both cars move with a velocity of 18.099 m/s in the direction of 15.945° downward from the x-axis (east)

7 0

3 years ago

Read 2 more answers