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svet-max [94.6K]
3 years ago
13

A woman stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.64

of her regular weight. Calculate the magnitude of the acceleration of the elevator.
Physics
1 answer:
Galina-37 [17]3 years ago
6 0

Answer:

The downwards acceleration is 3.53 m/s2.

Explanation:

Let the true weight is m g.

The reading of the balance, R = 0.64 mg

Let the acceleration is a.

As the apparent weight is less than the true weight so the elevator goes down wards with some acceleration.

Use Newton's second law

m g - R = m a

m g - 0.64 m g = m a

0.36 g = a

a = 3.53 m/s2

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(a) 0.249 (24.9 %)

The maximum efficiency of a heat engine is given by

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With constant angular acceleration \alpha, the disk achieves an angular velocity \omega at time t according to

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c. After 1.00 s, the disk has instantaneous angular velocity

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\theta=\left(42.0\dfrac{\rm rad}{\rm s}\right)(1.00\,\mathrm s)+\dfrac12\left(42.0\dfrac{\rm rad}{\mathrm s^2}\right)(1.00\,\mathrm s)^2=63.0\,\mathrm{rad}

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