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Mariana [72]
4 years ago
14

What energy is a quarterback’s arm before throwing a pass

Chemistry
2 answers:
Slav-nsk [51]4 years ago
5 0

Answer:

Potential Energy

Explanation:

Potential energy is the energy available when a body is at a state of rest or in virtue of its position. Its formula is mgh.

The quarter back’s hasn’t thrown the ball yet even though it has the potential to do so later on which makes it possess

Potential energy.

As soon as the arm moves and the ball is thrown, the potential energy is converted to Kinetic energy . The kinetic energy is the energy available as a result of the motion(movement) of a body.

Lunna [17]4 years ago
3 0

Potential energy


Reason why: because the quarterbacks arm has the potential to throw a ball but since it is not throwing the ball, the energy is being held... this holding of energy is called potential energy

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Explanation:

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Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?
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Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

                               C     +     O2      ------>  CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2. 

                          <u>     86.5 g CO       </u>   = 1.966 moles CO2
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Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel. 

        1.966 moles CO2   x   <u>   1 mole C   </u>    x   <u>   </u><u>12 g C   </u>  = 23.59 g C
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We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams. 


            25.0 g - 23.59 g = 1.41 grams Hydrogen 

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen. 

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel, 

Carbon:     <u>  1.966 mol   </u>   = 1.408   x   5 (factor)     = 7
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Hydrogen:  <u>  1.396 mol   </u>    = 1.00   x    5 (factor)    = 5
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Thus, the empirical formula is C7H5

       
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Answer:

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