What are the components of a vector with a magnitude of 4.00 and a direction of -112°?

Andy pushes a box to the right with 5 N of force. Kristen pushes the box to the left with 3 N of force. What will be the resulti

REY [17]

The forces are applied in opposite direction.
So the net force will be the difference of both forces.
net force =5-3=2N

This force will be in direction of 5N(bigger force) means in direction which Andy is pushing.

6 0

3 years ago

The distance from home plate to the pitchers mound is 18.5 meters. For a pitcher capable of throwing at 3.85m/s(86mi/hr), how mu

Taya2010 [7]

Given that:

Distance , s = 18.5 m

Velocity , v = 3.85 m/s

Time , t =?

Since,

Velocity = distance/time

or

Time= distance/velocity

time= 18.5/ 3.85

time= 4.8 s

So the time elapse between the release of the ball and the ball passing home plate is 4.8 seconds.

7 0

3 years ago

A car is traveling at a speed of 38.0 m/s on an interstate highway where the speed limit is 75.0 mi/h. Is the driver exceeding t

lidiya [134]

Answer:

Yes, the car driver is exceeding the given limit.

Explanation:

<u>Given:</u>

Speed of the car, v = 38.0 m/s.
Speed limit of the highway, $\rm v_o=75.0\ mi/h.$

<h2><u>Converting the speed limit from mi/h to m/s:</u></h2>

We know,

1 mi = 1.60934 km.

1 km = 1000 m.

Therefore, 1 mi = 1.60934 × 1000 m = 1609.34 m.

1 hour = 60 minutes.

1 minute = 60 seconds.

Therefore, 1 hour = 60 × 60 seconds = 3600 seconds.

Using these values,

$\rm 1\ \dfrac{mi}{h}=\dfrac{1609.34\ m}{3600\ s}=0.447\ m/s.$

Therefore,

$\rm v_o = 75.0\ mi/h=75.0\times 0.447=33.52\ m/s.$

Clearly,

$\rm v_o$

which means, the car driver is exceeding the given speed limit.

6 0

3 years ago

An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance

bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 $\frac{m}{sec}$

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion $V^{2}$ = $u^{2}$ - 2 a s

Put all the values in above formula we get,

⇒ 0 = $0.8^{2}$ - 2 × a ×0.2667

⇒ a = 1.2 $\frac{m}{sec^{2} }$

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0

3 years ago

How much support force does a table exert on a book that weighs 15 N when the book is placed on the table?

mestny [16]

Answer:

15 N

Explanation:

According to Newton's third law of motion, to every action, there is an equal and opposite reaction. This reaction is equal in magnitude to the force acting but in an opposite direction.

Now, if the book weighs 15 N, an opposite equal force will be: N = -15 N

But the magnitude of this will be the absolute value which is 15N.

8 0

3 years ago