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miv72 [106K]
4 years ago
7

One gallon of paint (volume = 3.79 10-3 m3) covers an area of 17.8 m2. What is the thickness of the fresh paint on the wall?

Physics
1 answer:
AURORKA [14]4 years ago
6 0

Answer:

0.2129 mm

Explanation:

We have given volume of the paint = 1 gallon=3.79\times 10^{-3}m^3

Area that covers the paint =17.8 m^2

We have to find the thickness of the fresh paint

So thickness=\frac{volume}{area}=\frac{3.79\times 10^{-3}}{17.8}=0.2129\times 10^{-3}m=0.2129mm

So the thickness of fresh paint on the wall is 0.2129 mm

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A wind turbine is initially spinning at a constant angular speed. As the wind's strength gradually increases, the turbine experi
Greeley [361]

:Answer:

a. the initial angular velocity = 166.5rad/s

b. t= 135.7seconds

Explanation:

a. v = rw

angular velocity for 2870 rev, w = (2πN)/60 =2*3.142*2870rev)/60 =300.5rad/sec

w₁-w₂ = 300.5 - 133= 166.5rad/s

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acceleration = change in velocity / time

b. 1 revolution = 2π

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=2870*1)/0.159 = 18050.3rad

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7 0
3 years ago
If the clothing maker bought 500 m2 of this fabric, how much money did he lose? Use 1tepiz=0.625dollar and 0.9144m=1yard.'
xenn [34]


1 yard^2 = 0.8361m^2.? 
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.


<span>So he spent (.625 x 400) = $250.00 per m^2. </span>
<span>He paid out (500 x 250) = $125,000 on the deal. </span>
<span>He received (500 / 0.8361) = 598.014592 yard^2 of fabric. </span>
<span>That would have cost (598.014592 x 120) = $71,761.75 locally. </span>
<span>He lost (125,000 - 71,761.75) = $53,238.25 on the deal. </span>

You can rework with the incorrect conversion factor.
3 0
3 years ago
A sample of gold has a mass of 38.6 grams and a volume of 2 cm3. What is the density of gold
Natali5045456 [20]

Answer:

19.3 g/cm^3

Explanation:

The density of a material is given by

\rho = \frac{m}{V}

where

m is the mass of the sample

V is its volume

for the sample of gold in this problem,

m = 38.6 g

V=2 cm^3

Substituting into the formula, we find the density of gold:

\rho = \frac{38.6}{2}=19.3 g/cm^3

5 0
3 years ago
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