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faltersainse [42]
3 years ago
6

A 1.65 mol sample of an ideal gas for which Cv,m = 3R/2 undergoes the following two-step process:1) from an initial state of the

gas described by T = 14.5degrees C and P = 2.00 x 104 Pa, the gas undergoes anisothermal expansion against a constant external pressure of 1.00 x104 Pa until the volume has doubled.2) subsequently the gas is cooled at constant volume. Thetemperature falls to -35.6 degrees C.Calculate q, w, , and for each step and for the overallprocess.

Physics
1 answer:
kirill [66]3 years ago
7 0

Answer:

W = -1.97KJ, Q = 1.97KJ, Delta U = 0

Delta U = -1.03KJ, Q = -1.03KJ, Delta H = -1.72KJ

Explanation:

The deatiled step by step calculation using the ideal gas equation (Pv =nRT), The first law of thermodynamics ( dQ =dW + dU) as applied is as shown in the attached file.

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Explanation:

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GaryK [48]

Explanation:

The given data is as follows.

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Let us assume that time necessary for report of rifle to reach the observer is t and will be calculated as follows.

               t = \frac{24.7}{343}      (velocity in air = 343 m/s)

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Now, before the observer hears the report the distance traveled by the bullet is as follows.

               d_{b} = c_{b} \times t

                          = 814.8 \times 0.072

                          = 58.66

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Thus, we can conclude that each bullet will travel a distance of 59 m.

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3 years ago
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