Question

A 1.65 mol sample of an ideal gas for which Cv,m = 3R/2 undergoes the following two-step process:1) from an initial state of the gas described by T = 14.5degrees C and P = 2.00 x 104 Pa, the gas undergoes anisothermal expansion against a constant external pressure of 1.00 x104 Pa until the volume has doubled.2) subsequently the gas is cooled at constant volume. Thetemperature falls to -35.6 degrees C.Calculate q, w, , and for each step and for the overallprocess.

Answer 1

Answer:

W = -1.97KJ, Q = 1.97KJ, Delta U = 0

Delta U = -1.03KJ, Q = -1.03KJ, Delta H = -1.72KJ

Explanation:

The deatiled step by step calculation using the ideal gas equation (Pv =nRT), The first law of thermodynamics ( dQ =dW + dU) as applied is as shown in the attached file.