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Charra [1.4K]
3 years ago
7

Visible light energy.

Physics
2 answers:
Ipatiy [6.2K]3 years ago
6 0
What about it??

Please explain and I will help.

I don’t know what you’re asking.
Leto [7]3 years ago
6 0

Answer:

No se pregunta a alguien mas carnalito.

Explanation:

Lo siento:(

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A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of
Fittoniya [83]

The acceleration of the air plane is 3.879 \mathrm{m} / \mathrm{s}^{2}

<u>Explanation:</u>

Given:

The mass of the air plane = 1492.3 kg

Force of each four engine = 1447.5 N

So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N

The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

                         \text {Force }(F)=m \times \text { acceleration }(a)

The above equation can be written as below to find acceleration,

                        a=\frac{F}{m}

Now. Substitute the given values, we get,

                        a=\frac{5790}{1492.3}=3.879 \mathrm{m} / \mathrm{s}^{2}

3 0
3 years ago
Assume a beam of light hits the boundary separating medium 1, with index of refraction n1 and medium 2, with index of refraction
Reptile [31]

Answer:

option C

Explanation:

Given,

Refractive index of medium 1 = n₁

Refractive index of medium 2 = n₂

For total internal reflection to take place light should move from denser medium to the rarer medium.

Here Total internal reflection take place at the boundary of medium 1 and medium 2 so, the refractive index of medium 1 is more than medium 2

 n₁ > n₂

The correct answer is option C

3 0
3 years ago
Un objeto de 200 gramos está amarrado del extremo de una cuerda y gira describiendo un círculo horizontal de 1.20 m de radio a r
vesna_86 [32]

Answer:

La tensión es 85.3 N.

Explanation:

Cuando el objeto gira en dirección horizontal, la sumatoria de fuerzas se puede calcular usando la segunda ley de Newton:  

\Sigma F_{x} =ma_{c}

T = ma_{c}  

Dado que el movimiento es horizontal, el peso (que está en el eje y) no contribuye en la sumatoria de fuerzas en el eje x. Por lo que la única fuerza actuando sobre el objeto en la dirección del movimiento es la tensión.  

En donde:                                          

m: es la masa del objeto = 200 g = 0.200 kg

a_{c}: es la aceleración centrípeta

La aceleración centrípeta viene dada por:  

a_{c} = \omega^{2} r

En donde:    

ω: es la velocidad angular del objeto = 3 rev/s

r: es el radio = 1.20 m

Entonces, la tensión es:

T = m\omega^{2} r = 0.200 kg(3\frac{rev}{s}*\frac{2\pi rad}{1 rev})^{2}*1.20 m = 85.3 N

   

Por lo tanto, la tensión es 85.3 N.  

Espero que te sea de utilidad!                                                                          

5 0
3 years ago
How much work is done (in Joules) by a weightlifter in raising a 60-kg barbell from the floor to a height of 2m? Work done =
Vika [28.1K]

Answer:

1176 Nm or J

Explanation:

W = F*d

F = 60kg * 9.8 kgm/s^2 = 588 N

W = 588 N * 2m = 1176 N*m

7 0
3 years ago
Read 2 more answers
One of the foci for the moon's orbit would be the
suter [353]
The question is oversimplified, and pretty sloppy.

Relative to the Earth . . .
The Moon is in an elliptical orbit around us, with a period of
27.32... days, and with the Earth at one focus of the ellipse.

Relative to the Sun . . .
The Moon is in an elliptical orbit around the Sun, with a period
of 365.24... days, and with the Sun at one focus of the ellipse,
and the Moon itself makes little dimples or squiggles in its orbit
on account of the gravitational influence of the nearby Earth.

I'm sorry if that seems complicated.  You know that motion is
always relative to something, and the solar system is not simple.
5 0
3 years ago
Read 2 more answers
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