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MakcuM [25]
4 years ago
8

Given the reaction: S + O2 ---> SO2

Chemistry
1 answer:
saul85 [17]4 years ago
3 0

Answer: 67.1 moles of SO2

Explanation:

Since the equation is already balanced, you would just need to cancel out the O2 and multiple the 67.1 mol by the 1 mol of SO2 to get your answer.

You might be interested in
The enthalpy change for converting 1.00 mol of ice at -25.0 °c to water at 70.0 °c is __________ kj. the specific heats of ice
Margarita [4]
Answer is: 6,16 kJ.
1) changing  temperature of ice from -25°C to 0°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 2 J/g·°C · 25°C 
Q₁ = 900 J.
m(H₂O) = 1mol · 18 g/mol = 18 g.
C - <span>specific heat of ice.
</span>2) changing temperature of water from 0°C to 70°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 4,18 J/g·°C · 70°C 
Q₁ = 5266,8 J.
C - specific heat of water.
Q = Q₁ + Q₂ = 900 J + 5266,8 J
Q = 6166,8 J = 6,16 kJ.

8 0
3 years ago
476.2 cm^3 to L<br> Express your answer to four significant figures.
lina2011 [118]

Answer:

107986178.7

107000000

6 0
4 years ago
What is the mass of the hydrogen peroxide that exactly fills a 200.0 mL container? The density of ethyl alcohol is 0.789 g/mL.
Tom [10]

Answer:

290 g of hydrogen peroxide would fill the 200.0 mL container

Explanation:

Given data:

Volume = 200.0 mL  

Mass of hydrogen peroxide = ?

Solution:

Density of hydrogen peroxide is 1.45 g/cm³.

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Now we can determine the mass of hydrogen peroxide.

D = m/v

1.45 g/cm³ = m/ 200.0 mL

1 mL = 1 cm³

m = 1.45 g/cm³× 200.0 cm³

m = 290 g

So 290 g of hydrogen peroxide would fill the 200.0 mL container.

5 0
4 years ago
Pb(OH)Cl, one of the lead compounds used in ancient Egyptian cosmetics, was prepared from PbO according to the following recipe:
sladkih [1.3K]

Answer:

8.59 g

2.25 g

Explanation:

According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-

Moles of Pb(OH)CL is

= \frac{Mass}{Molar\ mass}

= \frac{10.0 g}{259.65g / mol}

= 0.0385 mol

Mass of PbO needed is

= 0.385mol Pb(OH) Cl\times \frac{1 mol PbO}{1molpb (OH) cl} \times \frac{223.2g PbO}{1mol PbO}

After solving the above equation we will get

= 8.59 g

Mass of NaCL needed is

= \frac{1mol\ NaCl}{1molPb\ (OH)Cl} \times \frac{58.45NaCl}{1mol NaCl}

After solving the above equation we will get

= 2.25 g

Therefore we have applied the above formula.

7 0
3 years ago
An empty graduated cylinder weighs 55.26 g. When filled with 50.0 mL of an unknown liquid, it weighs
marysya [2.9K]

Answer:

.743 g/mL

Explanation:

Hopefully this helps :)

5 0
3 years ago
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