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saw5 [17]
3 years ago
8

The tangent line needs to touch 0.6, did i draw it correctly? ​

Physics
2 answers:
AleksandrR [38]3 years ago
8 0
Here you go! Did you get my answer?
Reil [10]3 years ago
3 0

Answer:

YES SURE

Explanation:

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A bullet 2cm log is fired at 420m/s and passes straight a 10cm thick board exiting at 280m/s
Sonbull [250]
Solving for the acceleration of the bullet

acceleration = (vf^2 – vi^2) / 2d

acceleration = ((280 m/s)^2 – (420 m/s)^2) / (2 * 0.12 m)

acceleration = (78400 - 176400) / 0.24 m

acceleration = -98000 / 0.24

acceleration = -408333 m/s^2

Solving for contact time with board

t^2 = 2d/a

t^2 = 2 * 0.12 m / 408333 m/s^2

t^2 = 0.24 m / 408333 m/s^2

t^2 = 5.8775558 x 10^-7

t = 0.0007666 s or 767 microseconds


(I was only able to do A and B)
7 0
3 years ago
Read 2 more answers
I need help with question 4
stellarik [79]
See if it’s answer A
5 0
2 years ago
___meaning two' sugar (or saccharide) units in a chain.
ludmilkaskok [199]
The answer is c

Explanation:
3 0
2 years ago
A sanding disk with rotational inertia 1.2 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of 10 N·m a
tensa zangetsu [6.8K]

Answer:

Angular momentum = 0.7 kg.m²/s

Angular velocity = 583.3 rad/s

Explanation:

1. The torque τ  is related to the angular momentum L by the relation

τ = ΔL/Δt

ΔL = τΔt

τ = 10 N. m

Δt = 70 ms = 70 × 10⁻³s

ΔL = (10 N. m) × (70 × 10⁻³s) = 700 × 10⁻³ kg.m²/s = 0.7 kg.m²/s

2. The rotational inertia I relates the angular momentum L to the angular velocity w

L = Iw

w = L/I

L =  0.7 kg.m²/s

I = 1.2 × 10⁻³ kg.m²

w = (0.7 kg.m²/s)/(1.2 × 10⁻³ kg.m²) = 583.3 rad/s

4 0
3 years ago
Someone help me, I'm stuck
Bas_tet [7]
C is the answer hope that helps you
3 0
2 years ago
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