Ask question

Ask question

All categories

4 years ago

9

The momentum of an object is proportional to its weight and speed. a. true b. false

1 answer:

Crank4 years ago

4 0

It would be A.. True

You might be interested in

The sun is lower in the sky during the winter than it is during the summer. (a) how does this change affect the flux of sunlight

Svetradugi [14.3K]

the correct answer is a

8 0

3 years ago

A sound wave has a wavelength of 0.450 meters. If its speed in cold air is 330 meters/second, what is the wave's frequency?

faust18 [17]

Most of the information's required are already given in the question. Based on those information's the answer can be easily deduced.
Wavelength of the sound wave = 0.450 meters
Speed of the sound wave = 330 meters per second
We already know
v=f<span>λ
</span>330 = f * 0.450
f = 330/0.450
= 733.33 hertz
So the frequency of the wave is 733.33 hertz

5 0

4 years ago

Read 2 more answers

Objects that rest have no forces upon them

Pani-rosa [81]

Answer:

false

Explanation:

every object will always have the force of gravity acting upon it.

6 0

3 years ago

Two parallel square metal plates that are 1.5 cm and 22 cm on each side carry equal but opposite charges uniformly spread out ov

Mumz [18]

Answer:

The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

Explanation:

Given that,

Distance =1.5 cm

Side = 22 cm

Electric field = 18000 N/C

We need to calculate the capacitance in the metal plates

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times(22\times10^{-2})^2}{1.5\times10^{-2}}$

$C=0.285\times10^{-10}\ F$

We need to calculate the potential

Using formula of potential

$V=Ed$

Put the value into the formula

$V=18000\times1.5\times10^{-2}\ V$

$V=270\ V$

We need to calculate the charge

Using formula of charge

$Q=CV$

Put the value into the formula

$Q=0.285\times10^{-10}\times270$

$Q=76.95\times10^{-10}\ C$

Here, the charge on both the positive and negative plates

$Q=+76.95\times10^{-10}\ C$

$Q=-76.95\times10^{-10}\ C$

We need to calculate the number of excess electrons are on the negative surface

Using formula of number of electrons

$n=\dfrac{q}{e}$

Put the value into the formula

$n=\dfrac{76.95\times10^{-10}}{1.6\times10^{-19}}$

$n=4.80\times10^{10}\ electrons$

Hence, The number of excess electrons are on the negative surface is $4.80\times10^{10}\ electrons$

8 0

3 years ago

Your new pet kitten is trapped in a ten foot deep hole. You need a contraption to safely rescue your poor animal. How can I solv

Amanda [17]

You could use a ladder or a rope

5 0

3 years ago