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scoundrel [369]
2 years ago
9

A body accelerate uniformly from rest at the rate of 3meters per seconds for 8 sec . calculate the distance covered by the body

during the acceleration
SOL​
Physics
1 answer:
pishuonlain [190]2 years ago
3 0

Answer:

96 m

Explanation:

Given:

v₀ = 0 m/s

a = 3 m/s²

t = 8 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (8 s) + ½ (3 m/s²) (8 s)²

Δx = 96 m

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omeli [17]

Answer:

Option D

Explanation:

Taking 2020 unit test for edu right now.

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3 years ago
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You kick a soccer ball with a mass of 2 kg. The ball leaves your foot with a speed of 30 m/s. How much kinetic energy does the b
Lyrx [107]

Answer:

KE= 900 (I think)

Explanation:

KE=½mv²

KE= ½(2)(30)²

KE=½(60)²

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Why does a balloon stick to a wall questions and problems answers?
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7 0
3 years ago
so I know you can solve this either by using Vox or Voy. I'm getting 3.08s when using Vox and 3.14s for Voy way. For Voy I'm usi
Tatiana [17]

The person's horizontal position is given by

x=v_0\cos40^\circ t

and the time it takes for him to travel 56.6 m is

56.6\,\mathrm m=\left(24.0\,\dfrac{\mathrm m}{\mathrm s}\right)\cos40^\circ t\implies t=3.08\,\mathrm s

so your first computed time is the correct one.

The question requires a bit of careful reading, and I think there may be a mistake in the problem. The person's vertical velocity v_y at time t is

v_y=v_{0y}-gt

which tells us that he would reach the ground at about t=3.15\,\mathrm s. In this time, he would have traveled

x=v_{0x}(3.15\,\mathrm s)=57.9\,\mathrm m

But we're told that he is caught by a net at 56.6 m, which would mean that the net cannot have been placed at the same height from which he was launched. However, it's possible that the moment at which he was launched doesn't refer to the moment the cannon went off, but rather the moment at which the person left the muzzle of the cannon a fraction of a second after the cannon was set off. After this time, the person's initial vertical velocity v_{0y} would have been a bit smaller than \left(24.0\,\frac{\mathrm m}{\mathrm s}\right)\sin40^\circ.

7 0
2 years ago
78 million in standard form
Leviafan [203]

Answer:

78 million in standard form is 78,000,000

6 0
3 years ago
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