An aluminium bar 600mm long1 with diameter 40mm, has a hole drilled in the centre of the bar. The hole is 30mm in diameter and i
s 100mm long. If the modulus of elasticity for the aluminium is 85GN/M^2 Calculate the total contraction on the bar due to a compressive load of 180KN
1 answer:
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Answer:
force between both the balloons is
Explanation:
It is given charge on both balloons are same and equal to
Separation between both the balloons
According to Coulomb's law force between two charges is given by
Therefore force is equal to
So force between both the balloons is
Let K.E
be the intial K.E and K.E
be new K.E,
I = 
K.E
--- (i)
K.E
Therefore,
K.E
----(ii)
Dividing i and ii,
I
K.E
K.E
Therefore,
K.E
Dividing i and ii,