0.56 A is the current of the secondary coil.
transformer is the device that transfer electric energy from one AC circuit to another.
we know that ;
I ∝ 1/n;
where I IS CURRENT and n is NUMBER OF TURNS.
(I) secondary = X A
(n) secondary = 100
(I) primary = 0.04 A
(n) primary = 1400
USING THIS-----> I ∝ 1/n;
=>
0.04 A/X A =100/1400
=>X=0.56 A
as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.
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Answer:
10kg
Explanation:
Let PE=potential energy
PE=196J
g(gravitational force)=9.8m/s^2
h(change in height)=2m
m=?
PE=m*g*(change in h)
196=m*9.8*2
m=10kg
Answer:

Explanation:
During the exchange of applied force, thermal energy is generated by the friction that exists between the ground and the tire.
Said force according to the statement is the reaction of half the force on the rear tire. In this way the normal force acted is,

The work done is given by the friction force and the distance traveled,

Where ![\mu_k [/ tex] is the coefficient of kinetic frictionN is the normal force previously found d is the distance traveled,Replacing,[tex]W_f = (0.80)(441)(0.42)](https://tex.z-dn.net/?f=%20%5Cmu_k%20%5B%2F%20tex%5D%20is%20the%20coefficient%20of%20kinetic%20friction%3C%2Fp%3E%3Cp%3EN%20is%20the%20normal%20force%20previously%20found%20d%20is%20the%20distance%20traveled%2C%3C%2Fp%3E%3Cp%3EReplacing%2C%3C%2Fp%3E%3Cp%3E%5Btex%5DW_f%20%3D%20%280.80%29%28441%29%280.42%29)
The thermal energy released through the work done is,
