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QveST [7]
4 years ago
7

An aluminium bar 600mm long1 with diameter 40mm, has a hole drilled in the centre of the bar. The hole is 30mm in diameter and i

s 100mm long. If the modulus of elasticity for the aluminium is 85GN/M^2 Calculate the total contraction on the bar due to a compressive load of 180KN

Physics
1 answer:
nexus9112 [7]4 years ago
6 0

Answer:

Total contraction = 1.2277 mm

Explanation:

the solution is given in the picture below and it is more explanatory

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Three children are at work.one is pushing a chair, another is pushing the sofa and the third one is pushing an empty trolley .wh
kari74 [83]

Answer:sofa

Explanation:the weight of the mass of that object can be heavy (er) than the rest

8 0
4 years ago
Validity of an experiment is based upon
igor_vitrenko [27]

Validity concludes the whole experimental values and concepts which makes that whether the results which are obtained meet all of the requirements of the scientific research method.

On which factors the validity of an experiment depends?

There are five components which are used in experiment: observations, questions, hypothesis, methods and results. The scientific method procedure is not only ensures that the same experiment can be repeated by other researchers, but this experiment is accepted. For example, there must have been arrange in a random way of the sample groups and proper work and care shows and the experiment is succeed.

So we can conclude that: Validity concludes the whole experimental values and concepts which makes that whether the results which are obtained meet all of the requirements of the scientific research method.

Learn more about Validity: brainly.com/question/25303029

SPJ1

4 0
2 years ago
10)<br> Ba<br> +<br> H2O<br> →<br> Ba(OH)2 +<br> H2<br><br><br><br> How do I balance this ?
Mashutka [201]

Answer:

That's the answer

Explanation:

If u need explanation I can. In the comments. I hope this satisfies you.

I also hope that u will make this the brainliest answer.

Have a nice day...

4 0
3 years ago
A car stands from rest and attains a speed of 20 m/s in 10 s. What distance will it cover ?​
sashaice [31]

Answer:

100m

Explanation:

100m

s=ut+1/2at^2

s= unknown, u=0, a=2, t=10

s=0*10+1/2(2)(10)^2

s=1/2(2)(100)

s=1(100)

displacement = 100 meters

4 0
3 years ago
If the frequency of the 13C signal of TMS is 201.16 MHz, the two 13C signals of acetic acid at 179.0 and 20.0 ppm are separated
Lelu [443]

The difference in frequency of the two signals is 1.33 \times 10^{10} \ kHz.

The given parameters;

  • <em>frequency of the 13 C signal = 201.16 MHz</em>

The energy of the 13 C signal located at 20 ppm is calculated as follows;

E = hf\\\\E_1 = h \frac{c}{\lambda} \\\\E_1 =  \frac{(6.626 \times 10^{-34})\times 3\times 10^8}{20 \times 10^{-6}} \\\\E_1 = 9.94 \times 10^{-21} \ J

The energy of the 13 C signal located at 179 ppm is calculated as follows;

E_2 = \frac{hc}{\lambda} \\\\E_2 = \frac{(6.626\times 10^{-34})\times (3\times 10^{8})}{179 \times 10^{-6} } \\\\E_2 = 1.11 \times 10^{-21} \ J

The difference in frequency of the two signals is calculated as follows;

E_1- E_2 = hf_1 - hf_2\\\\E_1 - E_2 = h(f_1 - f_2)\\\\f_1 - f_2 = \frac{E_1 - E_2 }{h} \\\\f_1 - f_2 = \frac{(9.94\times 10^{-21}) - (1.11 \times 10^{-21})}{6.626\times 10^{-34}} \\\\f_1 - f_2 = 1.33 \times 10^{13} \ Hz\\\\f_1 - f_2 = 1.33\times 10^{10} \ kHz

Thus, the difference in frequency of the two signals is 1.33 \times 10^{10} \ kHz.

Learn more here:brainly.com/question/14016376

4 0
3 years ago
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