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QveST [7]
3 years ago
7

An aluminium bar 600mm long1 with diameter 40mm, has a hole drilled in the centre of the bar. The hole is 30mm in diameter and i

s 100mm long. If the modulus of elasticity for the aluminium is 85GN/M^2 Calculate the total contraction on the bar due to a compressive load of 180KN

Physics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

Total contraction = 1.2277 mm

Explanation:

the solution is given in the picture below and it is more explanatory

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As temperature increases, ________. Group of answer choices the resistance of a conductor remains the same the resistance of a c
amm1812

Answer:

resistance of a conductor increases

Explanation:

The resistance of conductors is directly proportional to the temperature of the conductor. This implies that when the temperature of the conductor is increased, the resistance of the conductor increases likewise.

This is applied in the resistance thermometer. Resistance thermometers are useful for accurate temperature measurements at very high or very low temperatures.

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A quantity must be divided by multiples of ten when converting from a larger unit to a smaller unit.
sineoko [7]

Answer:

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If 34.7 g of O2 reacts with iron to form 79.34 g of iron oxide, how much iron was used in the reaction?
zhuklara [117]

Answer: B. 44.64 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Mass of reactants = mass of iron + mass of oxygen = mass of iron + 34.7 g

Mass of product = mass of iron oxide = 79.34 g

As Mass of reactants = Mass of product

mass of iron + 34.7 g = 79.34 g

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3 years ago
One hazard of space travel is the debris left by previous missions. There are several thousand objects orbiting Earth that are l
MariettaO [177]

Answer:

F = 6666.7 N

Explanation:

Given that,

Mass of a chip, m = 0.1 mg

Initial speed, u = 0

Final speed,v=4\times 10^{3}\ m/s

Time of collision,t=6\times 10^{-8}\ s

We know that,

Force, F = ma

Put all the values,

F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.1\times 10^{-6}\times (4\times 10^3-0)}{6\times 10^{-8}}\\\\F=6666.7\ N

So, the required force is 6666.7 N.

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A point moves on the x-axis in such a way that its velocity at time t (t > 0) is given by v=ln t/t . At what value of t does
Olenka [21]

Answer:

Explanation:

Given

Velocity of point is given by v=\frac{\ln t}{t}

To get maximum or minimum velocity differentiate v w.r.t t

\frac{\mathrm{d} v}{\mathrm{d} t}=\frac{\frac{1}{t}\times t-1\times \ln(t)}{t^2}

so 1-\ln (t) should be equal to zero

\ln (t)=1

t=e

i.e. t=2.718\ s

5 0
3 years ago
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