Answer:
Technician A is right. The situation will happens even with only two bulbs in series
Explanation:
We must take into account that
1.- All electric device need its nominal voltage to operate
2.-Any and all electric device means an electric load for the source in terms of equation that means any device will implies a drop voltage of V = I*R ( I the flows current and R the resistance of the device)
3.-Nominal voltage for bulbs are specify for houses voltages you find between fase and neutral wires for instance in Venezuela 120 (v).
4.-In a imaginary circuit of only one bulb, the nominal voltage will be applied and the bulb will operates correctly, but when you add another bulb (in series) the nominal voltage will split between the two bulbs ( we could find a situation such as the first bulb work properly but the second one does not). The voltage split according to Ohms law (in such way that the sum of voltage between the terminal of the first bulb plus the voltage at terminals of the second one are equal to nominal voltage.
For that reason all the bulbs are connected in parallel in wich case all of them will operate with the common voltage
The speed of an object that travels 400 km in 5 hours, would be calculated simply by taking the distance of 400 and dividing it by the number of hours 5.
400 km/5 hours = 80km/hr.
The speed is 80 km/hr.
Answer:
When the radius is doubled, its speed will be 42.42 km/h.
Explanation:
Given that,
The maximum speed around a level curve is 30 km/h = 8.34 m/s
We need to find the maximum speed around a curve with twice the radius. The maximum speed of the object is given by :
............(1)
If radius is doubled, r' = 2r
The maximum speed is given by :

..........(2)
Dividing equation (1) and (2) we get :



v' = 42.42 km/h
So, when the radius is doubled, its speed will be 42.42 km/h. Hence, this is the required solution.
Answer:
The image height is 0.00283 m or 0.283 cm and is inverted due to the negative sign
Explanation:
u = Object distance = 9 m
v = Image distance = 1.7 cm (as the image is forming on the retina)
= Object height = 1.5 m
Magnification

The image height is 0.00283 m or 0.283 cm and is inverted due to the negative sign