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3 years ago

What are the four basic units of electricity? provide the variable name and symbol, and unit name and symbol.

2 answers:

7 0

For the answer to the question above asking what are the four basic units of electricity?These are the four basic units of electricity: Voltage (V) Current (I) Power (P) Resistance (R)
Well, Ohm's Law states that 'the current drifting in a conductor is directly-proportional to the potential difference across the ends of that conductor, providing all physical conditions, such as temperature, remain constant'. 

As you can see, therefore, only two (not four!) quantities, current, and voltage, are specified. So only two units of measurement apply the ampere and the volt.

I hope my answer helped you. Feel free to ask more questions. Have a nice day!

Radda [10]3 years ago

6 0

The four basic units we use in the topic involving electricity are:

1. Volt (V) - used to express voltages
2. Ampere (A) - used for the electrical current
3. Ohm (Ω) - for electrical resistance
4. Watt (W) - for electric power

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Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to

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3 years ago

Pendulum A has a bob of mass m hung from the string of length L; pendulum B is identical to A except its bob has the length 2L.

GenaCL600 [577]

Answer:

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

Explanation:

For pendulum A: Length = L and gravity = g

The frequency of pendulum A is given by

$f = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$

Here, f is the frequency, L be the length

$f_{A} = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$ ... (1)

For pendulum B: Length = 2L, gravity = g

The frequency of pendulum B is given by

$f_{B} = \frac{1}{2\pi }\sqrt{\frac{g}{2L}}$ .... (2)

Divide equation (1) by (2)

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

5 0

3 years ago

What is dark energy? How is dark energy related to the theory of the multiverse?

PIT_PIT [208]

Answer:

Dark energy is the name given to the mysterious force that's causing the rate of expansion of our universe to accelerate over time, rather than to slow down. That's contrary to what one might expect from a universe that began in a Big Bang. Astronomers in the 20th century learned the universe is expanding

Explanation:

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3 years ago

A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resu

Sphinxa [80]

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k = 84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

3 0

3 years ago

Una ola oceánica viaja a aproximadamente 1,97 m / s. Esto es 4 millas por hora. La frecuencia de las ondas es de aproximadamente

yKpoI14uk [10]

Answer:

λ = 28,14 m

Explanation:

To find the wavelength of the wave you use the following formula:

$v=\lambda f$ (1)

v: speed of the wave = 1,97 m/s

λ: wavelength

f: frequency of the wave = 0,07 Hz

You replace the values of v and f in the equation (1) and solve for λ:

$\lambda=\frac{v}{f}=\frac{1,97m/s}{0,07Hz}=28,14m$

hence, the wavelength of the wave is 28,14 m

5 0

4 years ago