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2 years ago

What are the four basic units of electricity? provide the variable name and symbol, and unit name and symbol.

2 answers:

7 0

For the answer to the question above asking what are the four basic units of electricity?These are the four basic units of electricity: Voltage (V) Current (I) Power (P) Resistance (R)
Well, Ohm's Law states that 'the current drifting in a conductor is directly-proportional to the potential difference across the ends of that conductor, providing all physical conditions, such as temperature, remain constant'. 

As you can see, therefore, only two (not four!) quantities, current, and voltage, are specified. So only two units of measurement apply the ampere and the volt.

I hope my answer helped you. Feel free to ask more questions. Have a nice day!

Radda [10]2 years ago

6 0

The four basic units we use in the topic involving electricity are:

1. Volt (V) - used to express voltages
2. Ampere (A) - used for the electrical current
3. Ohm (Ω) - for electrical resistance
4. Watt (W) - for electric power

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Which 2 elements are most likely to react and form a compound? why?

Lina20 [59]

Lithium and Fluorine.

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2 years ago

Starting from rest, the Road Runner accelerates at 3 m/s for ten seconds. What is the final velocity of the Road Runner?

Charra [1.4K]

Answer

The answer to this question is $30 ms^{-1}$

Explanation

As we know that accelartion is the rate of change of velocity. So, it can be write as

$a = (V_f -V_i) /t$

where

$V_f$ is the final velocity

$V_i$ is the initial velocity

t is the time

a is the accelartion

as we konw

$a = 3 ms^{-2}$

t = 10 s

From rest So,

$V_i$ = 0

$V_f$ = ?

Putting values

$3 = (V_f - 0)/10$

$3 * 10 = V_f$

$30 = V_f$

$V_f = 30 ms^{-1}$

So, the right answe is $30 ms^{-1}$

6 0

2 years ago

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A car traveling west at 70 miles per hour for 3 hours covers a distance of

gtnhenbr [62]

70x3=210 mph... its that easy

5 0

2 years ago

The nearest star to the Earth is the red dwarf star Proxima Centauri, at a distance of 4.218 light-years. Convert this distance

alukav5142 [94]

Explanation:

The nearest star to the Earth is the red dwarf star Proxima Centauri, at a distance of 4.218 light-years.

Light year is the unit of distance covered by the heavenly bodies. 1 light year is equal to :

$1\ light\ year=3.72\times 10^{17}\ inches$

So, $4.218\ light\ year=4.218\times 3.72\times 10^{17}\ inches$

$4.218\ light\ year=1.56\times 10^{18}\ inches$

We need to convert 4.218 light-years barley corns.

Since, 1 barleycorn = 1/3 inch

$1\ inch=3\ barleycorn$

$1.56\times 10^{18}\ inches=3\times 1.56\times 10^{18}=4.68\times 10^{18}\ barleycorn$

So, the nearest star to the Earth is at a distance of $4.68\times 10^{18}\ barleycorn$ . Hence, this is the required solution.

3 0

3 years ago

The length of a certain wire is kept same while its radius is doubled. what is the new resistivity of this wire?

anastassius [24]

The text does not specify whether the resistance R of the wire must be kept the same or not: here I assume R must be kept the same.

The relationship between the resistance and the resistivity of a wire is
$\rho = \frac{AR}{L}$
where
$\rho$ is the resistivity
A is the cross-sectional area
R is the resistance
L is the wire length

the cross-sectional area is given by
$A=\pi r^2$
where r is the radius of the wire. Substituting in the previous equation ,we find
$\rho = \frac{\pi r^2 R}{L}$

For the new wire, the length L is kept the same (L'=L) while the radius is doubled (r'=2r), so the new resistivity is
$\rho' = \frac{\pi r'^2 R}{L'}= \frac{\pi (2r)^2 R}{L}=4 \frac{\pi r^2 R}{L} = 4 \rho$
Therefore, the new resistivity must be 4 times the original one.

5 0

3 years ago

Read 2 more answers