Answer:
f = 409 Hz
Explanation:
We have,
Length of the open organ pipe, l = 0.29 m
Frequency of vibration of second overtone, 
It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :
v is speed of sound
Let f is the fundamental frequency. It is given by :
The relation between f and f₂ can be written as :
So, the fundamental frequency of the pipe is 409 Hz.
Answer:
Distancia = 17,5 kilómetros.
Explanation:
Dados los siguientes datos;
Velocidad = 36 km/h
Tiempo = 0.5 horas
Para encontrar la distancia recorrida;
Distancia = velocidad * tiempo
Distancia = 35 * 0.5
Distancia = 17,5 kilómetros.
Por tanto, la distancia recorrida por el automóvil es de 17,5 kilómetros.
The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)
Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation
v = vo + at
When you plug in the values you get
v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.
Answer A
Explanation: because u need to make sure you know the difference between a need and a want
