Answer:
v' = 1.5 m/s
Explanation:
given,
mass of the bullet, m = 10 g
initial speed of the bullet, v = 300 m/s
final speed of the bullet after collision, v' = 300/2 = 150 m/s
Mass of the block, M = 1 Kg
initial speed of the block, u = 0 m/s
velocity of the block after collision, u' = ?
using conservation of momentum
m v + Mu = m v' + M u'
0.01 x 300 + 0 = 0.01 x 150 + 1 x v'
v' = 0.01 x 150
v' = 1.5 m/s
Speed of the block after collision is equal to v' = 1.5 m/s
25g of mass will require 25g of opposite force on the ball from the road and opposition is moving upward to work on the ball
Answer:
distance= 10 km
displacement= 7.21 km
Explanation:
distance= scalar (only magnitude)
displacement= vector (magnitude & direction)
distance= 6 km+ 4 km
= 10 km
displacement= shortest difference btwn 2 pts=
sqrt( 6^2+4^2)
sqrt(52)
7.21 km
Rod is 450mm and disk has a radius of 75mm So there is a pin holding the assembly upwards which is when Θ=0 and at the pin there is a torsional spring with constant of k=20N m/rad. One end of the rod is attached to the pin and the other is attached to the disk.
