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VladimirAG [237]
4 years ago
15

If you designed a rollercoaster, how might you design it? Would you have friction?

Physics
1 answer:
kvasek [131]4 years ago
4 0
Yes, because you would need friction to slow down the rollercoaster to a stop. 
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Consider this situation: A bucket of water, attached to a rope, is being pulled upward out of a well. Of the forces listed, iden
Sergio039 [100]
I know that E.) Tension Force is one of them and B.) Gravity Force but I'm not sure about the others.
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As light slows down, it bends or refracts. The index of refraction helps predict the amount of bending. How are the speed of lig
Eduardwww [97]
When light changes the medium it travels through it also changes speed. The speed in medium is given by formula:
v_{medium} = \frac{c}{ n_{medium} }

Rearranging formual gives:
n_{medium} = \frac{c}{ v_{medium} }

From this formula we can make conclusion that index of refraction is inversely proportional to speed of light in medium. This means that greater speed gives smaller index of refraction.
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4 years ago
Read 2 more answers
Four identical metallic objects carry the following charges 1.82 6.65 4.80 and 9.30 C The objects are brought simultaneously int
GuDViN [60]

Answer:

a) 5.64 C

b) 3.5*10¹⁹ protons

Explanation:

a)

  • Since the four metallic objects are identical, and total charge must be conserved, this means that after brought simultaneously into contact so that each touches the others, once separated, total charge must be the same than before being brought in contact.
  • But due they are identical, after charges were able to transfer freely between them, the four objects must have the same final charge, i.e. the fourth part of the total charge, as follows:

       Q_{n} = \frac{Q_{tot}}{4} = \frac{22.57C}{4} = 5.64 C  (1)

b)

  • This charge will be divided between n protons, since the charge is positive.
  • Since each proton carries a charge equal to the elementary charge e, which value is 1.6*10⁻¹⁹ C, we can find the number of protons in excess, doing the following calculation:
  • n_{p} =\frac{Q_{n}}{e} = \frac{5.64C}{1.6e-19C} = 3.5 e19 C (2)

7 0
3 years ago
2. El sonido de una ballena es en especial de frecuencia baja, pero existe una especie de ballena la Whalien cuya frecuencia es
ikadub [295]

Answer:

The sound of a whale is especially low frequency, but there is a species of whale the Whalien whose frequency is 52 Hz, if the propagation speed of the wave is 1400m / s What will be its period in the water and the air? And what will be the wavelength in each medium? Remember that the propagation speed in air is 340m / s

Explanation:

From wave equation, the speed, wavelength and frequency is related using

V = fλ

Where

V is the speed

f is the frequency

And λ is the wavelength

So,

The frequency of the whale is

f = 52Hz

The speed in water is V_w = 1400m/s

The speed in air is V_a = 340m/s

We want to find the period in each medium, the period is related to the frequency and since the frequency is constant.

Then, period in equal in both medium

T = 1 / f

T_w = T_a = 1 / f

T = 1 / 52

T = 0.0192 seconds

We want to find the wavelength in each medium

For water,

V = fλ

V_w = f × λ_w

Then,

λ_w = V_w / f.

λ_w = 1400 / 52 = 26.92 m

The wavelength in water is 26.92m

Now, in air

V = fλ

V_a = f × λ_a

Then,

λ_a = V_a / f.

λ_a = 340 / 52 = 6.54 m

The wavelength in air is 6.54 m

In Spanish

De la ecuación de onda, la velocidad, la longitud de onda y la frecuencia se relacionan usando

V = fλ

Dónde

V es la velocidad

f es la frecuencia

Y λ es la longitud de onda

Entonces,

La frecuencia de la ballena es

f = 52Hz

La velocidad en el agua es V_w = 1400m / s

La velocidad en el aire es V_a = 340m / s

Queremos encontrar el período en cada medio, el período está relacionado con la frecuencia y dado que la frecuencia es constante.

Luego, período igual en ambos medios

T = 1 / f

T_w = T_a = 1 / f

T = 1/52

T = 0.0192 segundos

Queremos encontrar la longitud de onda en cada medio

Para agua,

V = fλ

V_w = f × λ_w

Entonces,

λ_w = V_w / f.

λ_w = 1400/52 = 26,92 m

La longitud de onda en el agua es de 26,92 m.

Ahora en el aire

V = fλ

V_a = f × λ_a

Entonces,

λ_a = V_a / f.

λ_a = 340/52 = 6,54 m

La longitud de onda en el aire es de 6.54 m.

8 0
4 years ago
The most likely models of the planet Mercury indicate that more than half the planet may be composed of________.
Oxana [17]

Answer:

iron

Explanation:

4 0
3 years ago
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