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Shtirlitz [24]
3 years ago
9

Which of the following terms describes an accumulation of rocky, sandy, or clayey material deposited at the end of a glacier?

Chemistry
1 answer:
OLEGan [10]3 years ago
3 0

Answer:

Option (D)

Explanation:

<u>Eskers are the long ridges that are comprised of rocks, sands and clay particles and are deposited towards the end of the glaciers</u>. These are fluvioglacial depositional features. These particles are exposed after the glaciers recede. These ridges are formed parallel to the earlier flow direction of ice. The size of eskers is generally smaller as it carries smaller particles such as rocks, sands, and gravels, in comparison to the different type of moraines. It is because the flow velocity decreases as the glaciers melt. So, these eskers are formed at the end of the glaciers.

Thus, the correct answer is option (D).

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According to the kinetic molecular theory particles of matter
DiKsa [7]

Answer:

The kinetic molecular theory of matter states that: Matter is made up of particles that are constantly moving. ... Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles.

Explanation:

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3 years ago
At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 165 minutes, her sample has decayed to 5.
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The half-life equation is written as:

An = Aoe^-kt

We use this equation for the solution. We do as follows:

5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes? 
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE


Find a formula for G(t) , the amount of goo remaining at time t.G(t)=? 

G(t) = 176e^-0.02t

How many grams of goo will remain after 50 minutes? 

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Which of the following statements is true?
Ivan

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B.

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An aqueous solution is made by dissolving 26.4 grams of barium sulfide in 349 grams of water.
lukranit [14]

Answer:

Molality = 0.43 m

Explanation:

Given data:

Mass of barium sulfide = 25.4 g

Mass of water = 349 g (349 g/1000 = 0.349 Kg)

Molality of water = ?

Solution:

Number of moles of barium sulfide:

Number of moles = mass/molar mass

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Molality = number of moles o f solute/ Kg of solvent

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3 years ago
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