Answer:within the focal length of the lens, provided the focal length is shorter than the near point distance.
Explanation:Hope it helps
Answer:
Potential difference and charge will also increase.
Explanation:
Asking that :
What will happen to the charge and potential difference if the plate area were increased while the plate separation remains unchanged?
The charge is directly proportional to area of the plate. That is, increase in area of the plate of a capacitor will lead to the increase in the charges between the plates.
And since charge is also proportional to the magnitude of potential difference between the plates from the definition of capacitance of a capacitor which says that:
Q = CV
Therefore, increase in the area of the plate will also lead to increase in potential difference between the plates.
Therefore, if the plate area were increased while the plate separation remains unchanged, the charge and potential difference between them will also increase.
Yes basic, calculus, and trig
Answer: p = - {1/2} , q = {1/2}
Explanation: The frequency of oscillation of a pendulum is given as
F = 1/2π *√{l/g}
Where √ is square root
l is lenght
g is acceleration due to gravity
But
F = 1/T
Where T is the period of Oscillation
Making T subject of formula we have
T= 1/F
T = 2π√{g/l}
Here the power on l is -[1/2]= p
Also,
Power on g is 1/2 =q
All because of the square root.