Using the two kinematic equations that can be used for this problem are:
Vf = Vi + at and d=Vit +(1/2)*at^2
Since Vi (initial velocity) = 0
The equations can further be simplified where a is the acceleration, t is the time, Vf is the final velocity which is 70 miles per hour and d is 6 miles
Vf = at
70 = at
a = 70/t---equation 1
d=(1/2)*a*(t^2)
6 = (1/2)*a*(t^2) ---equation 2
Substituting equation 1 to equation 2.
6= (1/2)*(70/t)*(t^2)
6= 35t
t= 0.17142 hours or 10.28571 mins or 617.14 sec
The greater the cross sectional area of the condoctor<span>, the greater the number of electrons that move and contribute to the current. Having a larger current for the same </span><span>voltage means having a larger conductance. Since </span>resistance<span> is the </span>inverse<span> of conductance, </span>cross sectional area<span> is </span>inversely related<span> to the </span>resistance<span>.</span>
A transform fault boundary is the correct answer.
