Una cuerda de violin vibra con una frecuencia fundamental de 435 Hz. Cual sera su frecuencia de vibracion si se le somete a una
1 answer:
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Answer:
The magnitude of the force is 34.59 N.
Explanation:
Given that,
Inside pressure
Area
Outside pressure = 1 atm
We need to calculate the magnitude of the force
Using formula of force
Where, =inside Pressure
=outside Pressure
A = area
Put the value into the formula
Hence, The magnitude of the force is 34.59 N.
Answer:
option C
Explanation:
given,
force act on west = 20 lb
force act at 45° east of north = 80 lb
magnitude of force = ?
∑ F y = 80 cos 45⁰
F y = 56.57 lb
magnitude of forces in x- direction
∑ F x = -20 + 80 sin 45⁰
= 36.57 lb
net force
F =
F =
F = 67.36 lb≅ 67 lb
hence, the correct answer is option C
