To prevent static sparks that could occur while you fill fuel is that, a person who is filling the tank should remember that the nozzle of the fuel pump hose should always be in connected or in contact to the tank. This will prevent static sparks from happening to the boat that is going to be used and prevent harm to the person using or refilling the fuel.
Answer:
The expression for the initial speed of the fired projectile is:
And the initial speed ratio for the 9.0mm/44-caliber bullet is 1.773.
Explanation:
For the expression for the initial speed of the projectile, we can separate the problem in two phases. The first one is the moment before and after the impact. The second phase is the rising of the ballistic pendulum.
First Phase: Impact
In the process of the impact, the net external forces acting in the system bullet-pendulum are null. Therefore the linear momentum remains even (Conservation of linear momentum). This means:
(1)
Second Phase: pendular movement
After the impact, there isn't any non-conservative force doing work in al the process. Therefore the mechanical energy remains constant (Conservation Of Mechanical Energy). Therefore:
(2)
The height of the pendulum respect L and θ is:
(3)
Using equations (1),(2) and (3):
(4)
The initial speed ratio for the 9.0mm/44-caliber bullet is obtained using equation (4):
Answer:
W = 1014 J = 1.014 KJ
Explanation:
As, Sam has to stop the boats in the log ride. Therefore, the work Sam needs to do, in order to stop a boat must be equal to the kinetic energy of the boat:
Work Done by Sam = Kinetic Energy of the Boat
W = K.E
W = (1/2)mv²
where,
m = mass of boat and its rider = 1200 kg
v = speed of the boat = 1.3 m/s
Therefore,
W = (1/2)(1200 kg)(1.3 m/s)²
<u>W = 1014 J = 1.014 KJ</u>
Answer:
Label A: Battery, Label B: Light or Bulb, Label C: Switch
Explanation:
I got it right.
Answer:
F = 2349.6 N
Explanation:
We can solve this exercise using the relationship of momentum and momentum
I = Δp
I = F t
As the woman accelerates at a distance of 29.1 m to go from rest to 56.8 m / s, we can use the kinematics to find the acceleration
v² = v₀² + 2 a x
v₀ = 0
a = v / 2x
a = 56.8 2/2 29.1
a = 55.43 m / s²
Let's look for the time you need to get this speed
v = v₀ + a t
t = v / a
t = 56.8 / 55.43
t = 1,025 s
Let's clear the average force momentum from the momentum
F t = m v- m v₀
F = mv / t
F = 42.4 56.8 / 1.025
F = 2349.6 N