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OleMash [197]
3 years ago
13

The table shows the total number of electrons in Atom A and Atom B. Atom Number of Electrons A 10 B 18 Which statement is correc

t? A will give up electrons to form bonds. B will give up electrons to form bonds. Both A and B will be chemically unreactive. Both A and B will gain electrons to become stable.
Chemistry
2 answers:
HACTEHA [7]3 years ago
4 0

Answer:

Both A and B will be unreactive!

Explanation:

10=2, 8

18=2, 8, 8

suter [353]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

It is given that atom A contains 10 electrons so, its electronic distribution is 2, 8. Whereas atom B contains 18 electrons so, its electronic distribution is 2, 8, 8.

Since, both these atoms have completely filled octet so they do not need to react with any other element in order to attain stability.

Therefore, both these elements are unreactive in nature.

Thus, we can conclude that both A and B will be chemically unreactive.

You might be interested in
(6) Compare a CSTR with a PFR below. a. A flow of 0.3 m3/s enters a CSTR (volume of 200 m3) with an initial concentration of spe
Dmitry [639]

Answer:

Explanation:

Given that:

The flow rate Q = 0.3 m³/s

Volume (V) = 200 m³

Initial concentration C_o = 2.00 ms/l

reaction rate K = 5.09 hr⁻¹

Recall that:

time (t) = \dfrac{V}{Q}

time (t) = \dfrac{200}{0.3}

time (t) = 666.66 \ sec

time (t) = \dfrac{666.66 }{3600} hrs

time (t) = 0.185 hrs

\text{Using First Order Reaction:}

\dfrac{dc}{dt}=kc

where;

t = \dfrac{1}{k} \Big( \dfrac{C_o}{C_e}-1 \Big)

0.185 = \dfrac{1}{5.09} \Big ( \dfrac{200}{C_e}- 1 \Big)

0.942 =  \Big ( \dfrac{200}{C_e}- 1 \Big)

1+ 0.942 =  \Big ( \dfrac{200}{C_e} \Big)

\dfrac{200}{C_e} = 1.942

C_e = \dfrac{200}{1.942}

\mathbf{C_e = 102.98 \ mg/l}

Thus; the concentration of species in the reactant = 102.98 mg/l

b). If the plug flow reactor has the same efficiency as CSTR, Then:

t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196(0.663)

\dfrac{V_{PFR}}{0.3 hrs} =0.196(0.663)

\dfrac{V_{PFR}}{0.3*3600 sec} =0.196(0.663)

V_{PFR} =0.196(0.663)*0.3*3600

V_{PFR} = 140.34 \ m^3

The volume of the PFR is ≅ 140 m³

3 0
3 years ago
7. Buffalo were moved from Yellowstone National Park because
STALIN [3.7K]

Answer:

they had killed other animals

4 0
3 years ago
Read 2 more answers
What is the pH of a solution with an [H+] = 4.73x10^-7 M
Mice21 [21]

Answer:

The answer to your question is pH = 6.3

Explanation:

Data

pH = ?

[H⁺] = 4.73 x 10⁻⁷ M

pH is the measure of the concentration of [H⁺]. pH measures the acidity of the solution. If the value of pH is between 0 and 6.9, the solution is an acid. If the pH is 7.0 the solution is neutral and if the pH is between 7.1 and 14, the solution is an alkali.

Formula

pH = -log[H⁺]

Substitution

pH = -log[4.73 x 10⁻⁷]

-Simplification

pH = - (-6.3)

-Result

pH = 6.3

6 0
3 years ago
Which choice best describes what would happen if a cube with a density of 0.2 g/mL were placed in a container of water?
Andrew [12]

Answer:

A. It would float with about 80% of the cube below the surface of the water and 20% above the surface.

Explanation:

The choice that best describes what happens to cube of the given density value is that it would float with about 80% of the cube would be below the surface of the water and 20% above the surface.

Density is the mass per unit volume of a substance. The more mass a body has relative to volume, the great it's density. In short, density is directly proportional to mass and inversely related to volume.

The density of water is 1g/mL

If the density of the cube were to be the same with that of water, the substance will just mix up with water .

Here the density is less than that of water.

The density is 0.2g/mL

Therefore, 20% will stay afloat and 80% will be below the surface of the water.

5 0
3 years ago
There is a structure of CH3CH2CHCHCH2CH3, with a –CH2CH3 group attached to the third and fourth carbons.
NARA [144]

Explanation:

2,3-diethyl hexane

At first we select a long chain.

Then, we number that chain from that side where substituent position is closer.

Then, we write it's IUPAC name

Position of substituent + substituent name + chain name + suffix

Here,

2,3 + -diethyl + hex + -ane

= 2,3-diethyl hexane

7 0
3 years ago
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