Question

Bird bones have air pockets in them to reduce their weight–this also gives them an average density significantly less than that of the bones of other animals. suppose an ornithologist weighs a bird bone in air and in water and finds its mass is 43.0 g and its apparent mass when submerged is 3.60 g (the bone is watertight).a. what mass of water is displaced? b. what is the volume of the bone? c. what is its average density?

Answer 1

Answer:

39.4 g

39.4 cm³

1.09137 g/cm³

Explanation:

$\rho$ = Density of water = 1 g/cm³

Mass of water displaced will be the difference of the

$m=43-3.6\\\Rightarrow m=39.4\ g$

Mass of water displaced is 39.4 g

Density is given by

$\rho=\dfrac{m}{v}\\\Rightarrow v=\dfrac{m}{\rho}\\\Rightarrow v=\dfrac{39.4}{1}\\\Rightarrow v=39.4\ cm^3$

So, volume of bone is 39.4 cm³

Average density of the bird is given by

$\rho=\dfrac{43}{39.4}\\\Rightarrow \rho=1.09137\ g/cm^3$

The average density is 1.09137 g/cm³