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Gennadij [26K]
3 years ago
13

What is the push and pull of a man about to hit a golf ball with a golf club. Is it causing a change in SPEED, or DIRECTION, or

both?
Physics
1 answer:
ivanzaharov [21]3 years ago
5 0
It would be both speed and direction depending on the man's swing 
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As an object falls
Sidana [21]
As an object falls in response to gravitational force, its velocity increases
and its acceleration is unchanged.  On Earth, its acceleration is 9.8 m/s².
3 0
2 years ago
Read 2 more answers
What happens if your arrows are too lightly or heavily spined for your bow?
dmitriy555 [2]

Answer:

... If your arrows are too lightly or heavily spined for your bow, the “archer's paradox” resulting in poor arrow flight and loss of accuracy.

7 0
3 years ago
Drag the item from the item bank to its corresponding match.1.A fireman turns on his hose and is knocked backwards.2.It takes le
creativ13 [48]

Answer:

1 - third law

2 - second law

3 - first law

4 - third law

5 - second law

6 - first law

Explanation:

First law

In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force.

Second law

In an inertial frame of reference, the vector sum of the forces F on an object is equal to the mass m of that object multiplied by the acceleration, a of the object

F = ma.

Third law

When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.

7 0
3 years ago
Please any one help me
Hatshy [7]

Answer:

Which one are we supposed to do

Explanation:

4 0
3 years ago
During a goal-line stand, a 112-kg fullback moving eastward with a speed of 6 m/s
11111nata11111 [884]

Answer:

-1.24 m/s

Explanation:

Total momentum before collision = total momentum after collision

Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).

Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back  6 m/s (east), velocity of line back = -8 m/s (west). Hence:

Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s

The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.

Let velocity after collision be v, hence:

The total momentum after collision = (112 + 120)v = 232v

Total momentum before collision = total momentum after collision

-288 = 232v

v = -288 / 232

v = -1.24 m/s

Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).

7 0
3 years ago
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