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QveST [7]
3 years ago
6

A chemist makes a solution of NaOH for use in an experiment. She dissolves 0.00500 mol NaOH in 1.00 L H2O. The NaOH completely d

issociates to form a solution with [OH− ] = 0.00500 M. What is the pOH of this solution?
Chemistry
2 answers:
Mekhanik [1.2K]3 years ago
6 0

Answer:

C. 2.30

Explanation:

babymother [125]3 years ago
6 0

Answer:

C(2.30)

Explanation:

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Vesnalui [34]

Answer:

the answer would be A. cells

Explanation:

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7 0
3 years ago
V = d/t
dangina [55]

Answer:

Explanation:

Did you mean: V = d/t a = (V - Vit Average = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = -9.81 m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?

Showing results for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = "-9.81" m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?

Search instead for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = -9.81 m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?

7 0
2 years ago
Explain how lubricating the wheels of the skateboard can increase the speed of the girl
weqwewe [10]
Less friction to stop the wheel from turning
8 0
3 years ago
Read 2 more answers
In your own words, explain how gametes (the cells made for sexual reproduction) differ from normal body cells.
NNADVOKAT [17]

Answer:

gametes have to become haploid - they have to reduce their genetic material to a single copy, while somatic cells are diploid

Explanation:

7 0
2 years ago
Read 2 more answers
Ethylene produced by fermentation has a specific gravity of 0.787 at 25 degree Celsius. What is the volume of 125g of ethanol at
WITCHER [35]

<u>Answer:</u> The volume of given amount of ethanol at this temperature is 159.44 mL

<u>Explanation:</u>

Specific gravity is given by the formula:

\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}

We are given:

Density of water = 0.997 g/mL

Specific gravity of ethanol = 0.787

Putting values in above equation, we get:

0.787=\frac{\text{Density of a substance}}{0.997g/mL}\\\\\text{Density of a substance}=(0.787\times 0.997g/mL)=0.784g/mL

Density is defined as the ratio of mass and volume of a substance.

\text{Density}=\frac{\text{Mass}}{\text{Volume}} ......(1)

Given values:

Mass of ethanol = 125 g

Density of ethanol = 0.784 g/mL

Putting values in equation 1, we get:

\text{Volume of ethanol}=\frac{125g}{0.784g/mL}=159.44mL

Hence, the volume of given amount of ethanol at this temperature is 159.44 mL

6 0
3 years ago
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