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Rus_ich [418]
3 years ago
11

g In a cold rolling operation, steel sheets that are initially 300 cm long X 80 cm wide X 8 cm thick are cold worked to 80 cm wi

de X 5 cm thick. What is the % cold working performed on this steel?
Physics
1 answer:
seropon [69]3 years ago
6 0

Answer:

100% cold working performed on this steel

Explanation:

Using the constant volume assumption:

                L₀W₀t₀ (initial)                                    =                      Lₐ Wₐ tₐ (final)

thus 300 cm long X 80 cm wide X 8 cm thick =   Lₐ x 80 cm wide X 5 cm thick

Lₐ = 300 cm long X 80 cm wide X 8 cm thick/80 cm wide X 5 cm thick

  =480 cm

% cold working performed on this steel = Lₐ Wₐ tₐ (final) /  L₀W₀t₀ (initial) 8 100

= 480 x 80 x 5/ 300 x 80 x 8 *100 = 100%

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15

Explanation:

0.15 is a decimal place after a 0, whereas the 15 is a whole number

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A car speeds up from 14 meters per second to 21 meters per second in 6 seconds. Whats the acceleration and the distance passed w
Solnce55 [7]

Answer:

a = 1.666... m/s²

Explanation:

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Which of Newton’s Laws involves mass and acceleration? Question 1 options: 3rd 1st 2nd All of them
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6 0
4 years ago
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Julia jumps straight upward on mars, where the acceleration due to gravity is 3.7\,\dfrac{\text{m}}{\text{s}^2}3.7 s 2 m ​ 3, po
liberstina [14]

We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

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Time taken = 3 seconds

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So jumping velocity of Julia = 8 m/s

6 0
3 years ago
Boltzmann’s constant is 1.38066×10−23 J/K, and the universal gas constant is 8.31451 J/K · mol. If 1.9 mol of a gas is confined
Crazy boy [7]

Answer:

The average kinetic energy of a gas molecule is 8.49 × 10⁻²¹ J

Explanation:

According to Kinetic Molecular Theory, the average kinetic energy of gas molecules is a function only of temperature and is given by the equation:

E=\frac{3}{2}kT

pV=nRT;\\T=\frac{pV}{nR}

Substituting the value of T in the kinetic energy equation:

E=\frac{3kpV}{2nR}

Where p is the pressure of the gas = 9 atm = 9 × 101325 pa

k is the Boltzmann’s constant  =  1.38066 × 10⁻²³ J/K,

V is the volume of the gas = 7.1 L = 7.1 × 10⁻³ m³

n is the number of moles of the gas = 1.9 mol

R is the universal gas constant = 8.31451 J/K · mol.

E is the average kinetic energy of a gas molecule

Substituting values:

E=\frac{3kpV}{2nR}=\frac{3*1.38066*10^{-23}*9*101325*7.1*10^{-3}}{2*1.9*8.31451}=8.49*10^{-21}J

The average kinetic energy of a gas molecule is 8.49 × 10⁻²¹ J

6 0
3 years ago
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