What are the two factors that affect the friction force between two surfaces
1 answer:
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Answer:
(a) a = (2i + 4.5j) m/s^2
(b) r = ro + vot + (1/2)at^2
Explanation:
(a) The acceleration of the particle is given by:
vo: initial velocity = (3.00i -2.00j) m/s
v: final velocity = (9.00i + 7.00j) m/s
t = 3s
by replacing the values of the vectors and time you obtain:
(b) The position vector is given by:
where vo = (3.00i -2.00j) m/s and a = (2.00i + 4.50j)m/s^2
Answer:
F = 2325 N
Explanation:
given,
mass of the car, m = 1550 Kg
initial speed, u = 10 m/s
final speed, v = 25 m/s
time, t = 10 s
Average net force = ?
acceleration of the car
a = 1.5 m/s²
we know
F = m a
F = 1550 x 1.5
F = 2325 N
Net average force applied on the car is equal to 2325 N.