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kicyunya [14]
3 years ago
8

For the gas phase decomposition of nitrosyl chloride at 400 K , the rate of the reaction is determined by measuring the appearan

ce of Cl2 . 2 NOCl= 2 NO + Cl2 At the beginning of the reaction, the concentration of Cl2 is 0 M. After 1.64×103 min the concentration has increased to 3.39×10-3 M. What is the rate of the reaction?
Chemistry
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

2.067 x 10⁻⁷ M/min.

Explanation:

  • Knowing that the rate of the reaction is the change in the concentration of reactants (decrease) or the products (increase) with time.

  • For the reaction: <em>2NOCl ⇄ 2NO + Cl₂,</em>

<em>Rate of the reaction = - 1/2 d[NOCl]/dt = 1/2 d[NO]/dt = d[Cl₂]/dt</em>

∵ d[Cl₂] = 3.39 x 10⁻³ M, dt = 1.64 x 10³ min.

∴ Rate of the reaction = d[Cl₂]/dt = (3.39 x 10⁻³ M) / (1.64 x 10³ min) = 2.067 x 10⁻⁷ M/min.

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Answer:

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Hello,

a. By applying the given information, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8} =9.1x10^3gC_3H_8

b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8}*\frac{1molC_3H_8}{44gC_3H_8} =2.1x10^2molC_3H_8

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Q=-2043kJ/mol*2.1x10^2molC_3H_8\\Q=-4.6x10^5kJ

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answer attached

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