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kicyunya [14]
3 years ago
8

For the gas phase decomposition of nitrosyl chloride at 400 K , the rate of the reaction is determined by measuring the appearan

ce of Cl2 . 2 NOCl= 2 NO + Cl2 At the beginning of the reaction, the concentration of Cl2 is 0 M. After 1.64×103 min the concentration has increased to 3.39×10-3 M. What is the rate of the reaction?
Chemistry
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

2.067 x 10⁻⁷ M/min.

Explanation:

  • Knowing that the rate of the reaction is the change in the concentration of reactants (decrease) or the products (increase) with time.

  • For the reaction: <em>2NOCl ⇄ 2NO + Cl₂,</em>

<em>Rate of the reaction = - 1/2 d[NOCl]/dt = 1/2 d[NO]/dt = d[Cl₂]/dt</em>

∵ d[Cl₂] = 3.39 x 10⁻³ M, dt = 1.64 x 10³ min.

∴ Rate of the reaction = d[Cl₂]/dt = (3.39 x 10⁻³ M) / (1.64 x 10³ min) = 2.067 x 10⁻⁷ M/min.

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ss7ja [257]

<u>Answer:</u> The density of substance is 3.38g/cm^3

<u>Explanation:</u>

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of substance = 61.6 g

Volume of substance = 18.2cm^3

Putting values in above equation, we get:

\text{Density of substance}=\frac{61.6g}{18.2cm^3}\\\\\text{Density of substance}=3.38g/cm^3

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8 0
3 years ago
A rigid container of O has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?
tia_tia [17]

Answer:

P₂ = 130.18 kPa

Explanation:

In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:

P₁/T₁ = P₂/T₂   (1)

From here, we can solve for the Pressure at 273 K:

P₂ = P₁ * T₂ / T₁   (2)

Now, all we need to do is replace the given data and solve for P₂:

P₂ = 340 * 273 / 713

<h2>P₂ = 130.18 kPa</h2>

Hope this helps

4 0
3 years ago
The primary product of the combustion of sulfur is:
timama [110]
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3 years ago
Explain what makes insulative materials work most effectively.
KengaRu [80]

Answer:

Most common insulation materials work by slowing conductive heat flow and--to a lesser extent--convective heat flow. Radiant barriers and reflective insulation systems work by reducing radiant heat gain. To be effective, the reflective surface must face an air space.

Explanation:

To be effective, the reflective surface must face an air space.

6 0
4 years ago
How many grams of mercury would be contained in 15 compact fluorescent light bulbs?
zhenek [66]

Answer:

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Note: The question is incomplete. The complete question is as follows:

A compact fluorescent light bulb contains 4 mg of mercury. How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

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Since one fluorescent light bulb contains 4 mg of mercury,

15 such bulbs will contain 15 * 4 mg of mercury = 60 mg

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Compact fluorescent lightbulbs (CFLs) are tubes containing mercury and noble gases. When electricity is passed through the bulb, electron-streams flow from a tungsten-coated coil. They collide with mercury atoms, exciting their electrons and creating flashes of ultraviolet light. A phosphor coating on the inside of the tube absorbs this UV light flashes and re-emits it as visible light. The amount of mercury in a fluorescent lamp varies from 3 to 46 mg, depending on lamp size and age.

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