Answer:
The soil has a percentage of water by mass of 27.8 %.
Explanation:
Keeping in mind that
- Mass of Clay = Mass of water + Mass of Dry Soil
we can <u>calculate the mass of water</u>:
- 1350 g = Mass of Water + 975 g
We can then <u>calculate the mass percentage of water in the soil</u>:
- 375 / 1350 * 100% = 27.8 %
Answer:
25 liters of the 16% solution should be added.
Step by Step Explanation:
pure acid amount + pure acid amount = total pure acid amount
So,
0.02*10 + 0.16*x = 0.12*(10+x)
0.02*10 + 0.16x = 0.12*10 + 0.12*x
0.16*x - 0.12*x = 0.12*10 - 0.02*10
(0.16 - 0.12)*x = 0.12*10 - 0.02*10
x = (0.12*10-0.02*10)/(0.16-0.12)=25
Check: (0.2*10+0.16*25)/(10+25) = 0.12 = 12% of concentration of the final mixture. ! Correct !