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kicyunya [14]
3 years ago
8

For the gas phase decomposition of nitrosyl chloride at 400 K , the rate of the reaction is determined by measuring the appearan

ce of Cl2 . 2 NOCl= 2 NO + Cl2 At the beginning of the reaction, the concentration of Cl2 is 0 M. After 1.64×103 min the concentration has increased to 3.39×10-3 M. What is the rate of the reaction?
Chemistry
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

2.067 x 10⁻⁷ M/min.

Explanation:

  • Knowing that the rate of the reaction is the change in the concentration of reactants (decrease) or the products (increase) with time.

  • For the reaction: <em>2NOCl ⇄ 2NO + Cl₂,</em>

<em>Rate of the reaction = - 1/2 d[NOCl]/dt = 1/2 d[NO]/dt = d[Cl₂]/dt</em>

∵ d[Cl₂] = 3.39 x 10⁻³ M, dt = 1.64 x 10³ min.

∴ Rate of the reaction = d[Cl₂]/dt = (3.39 x 10⁻³ M) / (1.64 x 10³ min) = 2.067 x 10⁻⁷ M/min.

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For each compound determine whether it is organic or inorganic. C10h16kno9s2 naaso2 hsicl3 (ch)4as2 (bio)2co3 h2p2o7 h2o co2 c6h
Sindrei [870]

a. Organic: C₁₀H₁₆KNO₉S₂; (CH₃)₄As₂; C₆H₁₂O₆

b. Inorganic: NaAsO₂; HSiCl₃; (BiO)₂CO₃; H₂P₂O₇; H₂O; CO₂

Compounds containing <em>both C and H</em> are organic.

Compounds that are <em>not organic</em> are inorganic.

8 0
3 years ago
The density of liquid mercury is 13.6 g/mL. What is its density in units of ? (2.54 cm = 1 in., 2.205 lb = 1 kg)
nalin [4]

Correct question

The density of liquid mercury is 13.6 g/mL. What is its density in units of lb/in​3​? (2.5 cm = 1 in., 2.205 lbs= 1 kg., 1000 g =1 kg, 1 mL = 1 cm³)

Answer:

\rho0.4916\ lb/in^3

Explanation:

Given that;-

The density = 13.6 g/mL

Also, 1 kg = 2.205 lb

1 kg = 1000 g

So, 1000 g = 2.205 lb

1 g = 0.002205 lb

Also,

1 in = 2.54 cm

1 in³ = 16.39 cm³

1 cm³ = 1 mL

So,  1 in³ = 16.39 mL

1 mL = 0.061 in³

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

Thus,

\rho=\frac{13.6\ g}{1\ mL}=\frac{13.6\times 0.002205\ lb}{0.061\ in^3}=0.4916\ lb/in^3

7 0
3 years ago
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
How many moles of LiOH are required to make 4.2 liters of a 0.98 M
ASHA 777 [7]

Answer:

4.12 mol  

Explanation:

Given data:

Moles of LiOH  required = ?

Volume of solution = 4.2 L

Molarity of solution = 0.98 M

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

we will calculate the moles from above given formula.

0.98 M = number of moles / 4.2 L

0.98 M × 4.2 L = number of moles

Number of moles = 0.98 M × 4.2 L

Number of moles = 4.12 mol     (M = mol/L)

7 0
3 years ago
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Katarina [22]

Answer:A

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7 0
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