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Liula [17]
3 years ago
12

Which two scenarios illustrate the relationship between pressure and volume as described by Boyle’s law?

Chemistry
2 answers:
Airida [17]3 years ago
3 0

The correct answer is option 2 and 3.

The two scenarios that illustrate the relationship between pressure and volume as described by Boyle’s law are as follows:

2. The volume of an underwater bubble increases as it rises and the pressure decreases.

3. The pressure increases in an inflated plastic bag when the bag is stepped on.

According to Boyle's law, pressure of a gas is inversely proportional to its volume at constant temperature. This means that pressure rises as the volume increases and vice versa.

DaniilM [7]3 years ago
3 0

Answer:

2 and 3

Explanation:

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One and a half gallons of paint are used on refrigeration units which are then baked dry in a 275F oven for 2 hours. If the pain
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Answer:

Hence the evaporation rate in pints per minute is 0.001583.

Explanation:

Now,

1.5 gallons of paint are used.

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95% of 1.5 gallon=(95/100)*1.5 = 1.425 gallons.

1gallon = 8 pints.

So 1.425 gallons=8*1.425 pints

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4 0
2 years ago
Do you think one mole of the different substances has the same amount?​
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where

\\ \sf\longmapsto n=6.022\times 10^{23}

5 0
2 years ago
The rate law for the reaction 3a ⟶⟶ c is rate = 4. 36 x 10–2 l • mol–1 • h–1[ a ]2 how long will it take in hours for the concen
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The hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

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Rate law depicts the rate of a chemical reaction depend on the concentration of the reactant.

The given reaction is second order reaction

Thus, the hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

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brainly.com/question/8314253

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4 0
2 years ago
When a saturated solution of NH4Br dissolved in 100 grams of water is cooled from 60°C to 30°C, how much NH4Br will precipitate?
stepladder [879]

Answer:

m_{precipitated}=24.8g

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g

Best regards.

8 0
3 years ago
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