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kipiarov [429]
3 years ago
5

Complete the reaction, which is part of the electron transport chain. The abbreviation Q represents coenzyme Q. Use the appropri

ate abbreviation for the product. FADH2+Q⟶ The reactant that is reduced is . In complex III, electrons are transferred from coenzyme Q to cytochrome c, which contains iron. QH2+2cyt c(Fe3+)⟶Q+2cyt c(Fex)+2H+ Determine the oxidation number for iron on the right side of the reaction arrow. x
Chemistry
1 answer:
fredd [130]3 years ago
7 0

Answer:

x = 2+

Explanation:

1) FADH2 + Q => FAD + QH2

Since H is added to Q

=> Reactant reduced is Q

(2) Balancing charges on both sides of the equation gives:

QH2 + 2 cyt c(Fe3+) => Q + 2 cyt c(Fe2+) + 2 H+

Thus x = 2+

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In Thomson’s model of the atom , what parts of the atom were in motion
trasher [3.6K]

Answer:

The electrons where in motion

4 0
3 years ago
What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
pav-90 [236]

Answer:

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

Explanation:

ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

In our case we have:

mass of MgBr₂ = 12.41 g

volume of water (which is equal to the final solution volume) = 2.55 L

Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

then         X g of MgBr₂ are dissolved in 1 L of water

X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂

if in         184 g (1 mole) of MgBr₂ we have 160 g of Br⁻

then in   4.867 g of MgBr₂ we have Y g of Br⁻

Y = (4.867 × 160) / 184 = 4.232 g of bromide (Br⁻)

4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

7 0
3 years ago
Several constructive processes helped build mountains on Earth. All BUT one of these is a way mountains can be built. That is A)
Naddik [55]
It is landslides i got it right on the test 
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3 years ago
Which element experiences greater London dispersion forces
natali 33 [55]
Its d its the only one that makes sense


8 0
3 years ago
Calculate the theoretical yield of ammonia produced by the reaction of 100 g of H2 gas and 200g of N2 gas? 3H2(g) + N2(g)-----&g
Alex787 [66]
Moles of Hydrogen present: 100 / 2 = 50 moles

Moles of Nitrogen present: 200 / 28 = 7.14 moles

Hydrogen required by given amount of nitrogen = 7.14 x 3 = 21.42 moles

Hydrogen is excess so we will calculate the Ammonia produced using Nitrogen.

Molar ratio of Nitrogen : Ammonia = 1 : 2

Moles of ammonia = 7.14 x 2 = 14.28 moles
8 0
3 years ago
Read 2 more answers
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