Answer:
992
Step-by-step explanation:
You must convert the meter the kilometer by miltiplying by 1000
and when you do it you must multiply 0.992 by 1000 since it is a fraction .
or you can work it this way :
- 0.992⇒1m
- x(the new rate) ⇒1000m
- x= 0.992*1000= 992
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.
A=B
Method 1:
We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5
B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º ⇒ C=2*40º=80º
Answer:
a=7; A=50º
b=7; B=50º
<span>c=9; C=80º
Method 2:
Law of cosines:
a²=b²+c²-2bcCosA ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º
B=A=50º
A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º
Answer:
</span>a=7; A=50º
b=7; B=50º
<span>c=9; C=80º</span>
a^2 - b^2 = (a + b)(a - b)
In this case
49x^4y^2 - 4z^2
= (7x^2y)^2 - (2z)^2
= (7x^2y + 2z)(7x^2y - 2z)
Factors are (7x^2y + 2z) and (7x^2y - 2z)
Answer:
D) 7x^2y + 2z
Arctan (√3 /3) = 30°. = π/6 rad
That is the value searched, in degrees and radians.
You can verifiy that tan(30°) = sin(30°) / cos(30°) = [1/2] / [√3/2] = 1/√3 = √3 / 3
draw a perpendicular line from the directrix passing through the focus, this will be the line of symmetry.
The vertex(h, k) will be located on the line half way between the focus and directrix.
The distance from the focus to the vertex is called the focal length, call it a. The then equation is
(x - h)^2 = 4a(y - k)
the equation can be manipulated to
y = 1/4a(x - h)^2 + k
hope it helps
